Let's say you are on a tall building with a ball. You drop the ball and it accelerates with 9.81 m/s2 . But at the same time the ball is being pushed backwards or decelerated by the air resistance. As the velocity of the ball increases, the air resistance increases. This happens till the air resistance deceleration equals the gravitational pull acceleration. This is when the ball reaches terminal velocity as there is no net acceleration on the ball.
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Gravitational Pull only Small Air Resistance Gravitational Pull = Air resistance
Terminal velocity is the maximum attainable velocity of an object falling through a liquid or a gas. This happens when the resistance offered by the fluid increases with the increase in the magnitude of velocity. Eventually the object reaches terminal velocity as soon as the resistance becomes equal to the driving force.
It is a resistive force which acts opposite to the relative motion of an object with respect to a fluid. It is different from other resistive forces in the sense that it depends on the velocity of the object falling through the fluid. It is commonly referred to as air resistance or fluid resistance. Drag coefficient is a quantity that quantifies all the complexities of dependencies of resistive force and is dimensionless.
Drag force depends on the density, compressibility and the viscosity of the fluid , the square of the velocity of the object , the size and shape of the body, and inclination of the body towards the flow .Generally ,the dependence on other properties is complex to show Mathematically.
We can deal with these complex dependencies by characterizing them in a single variable. For drag, this variable is called the drag coefficient, designated Cd.The value of drag coefficient can be calculated by experimentation.
The drag equation states that drag D is equal to half of the density r times drag coefficient Cd times multiplied by the square of the velocity v of the object times the projected area.
D = 1/2ρv2ACd
Mathematical Representation of Terminal Velocity
VT = √2mg ∕ρACd
VT represents terminal velocity
m is the mass of the falling body
g is the acceleration due to gravity
A is the projected area of the object
ρ is the density of the fluid
Cd represents the drag coefficient
Derivation of Terminal Velocity
Drag equation gives-
D = 1/2ρv2ACd
Net force exerted on the body-
Fnet = ma = Gravitational force - Drag force
ma = mg - 1/2ρv2ACd
At equilibrium, F = 0 this implies
0 = mg - 1/2ρv2ACd
mg = 1/2ρv2ACd
By solving this,
VT = √2mg ∕ρACd
The example we discussed above can be represented graphically.
The velocity of the falling ball is increasing under the influence of the gravitational pull but the air resistance opposes this increase. Thus, at some point, both the forces cancel out and the ball attains maximum possible velocity.The velocity of the falling ball remains constant from that point
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Did you know?
Drag force of a fluid is ultimately a cause of the viscous force but surprisingly its Mathematical representation is independent of the viscosity of a fluid.
Buoyant force is also a type of resistive force which opposes the motion of a body in a fluid.
Evolution has forced birds to be streamlined to fly better to reduce drag and similarly fish to swim faster underwater.
Aerodynamic drag is responsible for the balance of aircrafts in the sky.
Terminal velocity of a human in air is 150m/s so if we fall on a water body with this much speed, there will be massive collateral damage.
A ball will have different terminal velocities on different planets due to change in their gravitational effect.