
What is the numerical value of one faraday?
A. 10000 C
B. 95000 C
C. 96.5 C
D. 96500 C
Answer
219.9k+ views
Hint: 1 Faraday is the charge of the 1 mole of the electron. 1mole is equivalent to $6.022\times {{10}^{23}}$ particles which may be atoms, molecules or ions. We know that the charge of an electron is (1.602$\times {{10}^{-19}}$ ). So by calculating the charge on 1mole of electrons we can get the desired result.
Complete step by step answer:
- 1 Faraday charge liberates one gram equivalent of substance at electrode. 1 faraday or faraday constant denoted by symbol F and this constant represents the magnitude of electric charge per mole of electrons. \[ F= {{e}^-}× {N_A}\] , where e is the charge of electrons in coulombs and \[{N_A}\] is the Avogadro constant.
Faraday constant=(1.602$\times {{10}^{-19}}$ )$\times $ ($6.022\times {{10}^{23}}$ )=96500 C.
Additional Information: Faraday constant is named after Michael Faraday. In chemistry and physics this constant represents the magnitude of electric charge per mole of electrons. One common use of this constant is in electrolysis calculations. One can divide the amount of charge in coulombs by the faraday constant in order to find the chemical amount of the element that has been oxidized.
> The value of F was first calculated by weighing the amount of silver deposited in an electrochemical reaction in which a measured current was passed for a measured time.
> In general for any electrochemical reaction, a measured value of current is made to pass for a certain time and the value of F was calculated by measuring the amount of silver deposited.
Note: The only difference between faraday unit of charge and faraday constant is that faraday unit of charge is represented by 96500C but faraday constant is represented by 96500 C/mol.
Complete step by step answer:
- 1 Faraday charge liberates one gram equivalent of substance at electrode. 1 faraday or faraday constant denoted by symbol F and this constant represents the magnitude of electric charge per mole of electrons. \[ F= {{e}^-}× {N_A}\] , where e is the charge of electrons in coulombs and \[{N_A}\] is the Avogadro constant.
Faraday constant=(1.602$\times {{10}^{-19}}$ )$\times $ ($6.022\times {{10}^{23}}$ )=96500 C.
Additional Information: Faraday constant is named after Michael Faraday. In chemistry and physics this constant represents the magnitude of electric charge per mole of electrons. One common use of this constant is in electrolysis calculations. One can divide the amount of charge in coulombs by the faraday constant in order to find the chemical amount of the element that has been oxidized.
> The value of F was first calculated by weighing the amount of silver deposited in an electrochemical reaction in which a measured current was passed for a measured time.
> In general for any electrochemical reaction, a measured value of current is made to pass for a certain time and the value of F was calculated by measuring the amount of silver deposited.
Note: The only difference between faraday unit of charge and faraday constant is that faraday unit of charge is represented by 96500C but faraday constant is represented by 96500 C/mol.
Recently Updated Pages
Electricity and Magnetism Explained: Key Concepts & Applications

JEE Energetics Important Concepts and Tips for Exam Preparation

JEE Isolation, Preparation and Properties of Non-metals Important Concepts and Tips for Exam Preparation

JEE Main 2021 July 25 Shift 1 Question Paper with Answer Key

JEE Main 2021 July 22 Shift 2 Question Paper with Answer Key

States of Matter Chapter For JEE Main Chemistry

Trending doubts
JEE Main 2026: Application Form Open, Exam Dates, Syllabus, Eligibility & Question Papers

Derivation of Equation of Trajectory Explained for Students

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Angle of Deviation in a Prism

Understanding Atomic Structure for Beginners

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
Solutions Class 12 Chemistry Chapter 1 CBSE Notes - 2025-26

NCERT Solutions For Class 12 Chemistry Chapter 1 Solutions - 2025-26

The D and F Block Elements Class 12 Chemistry Chapter 4 CBSE Notes - 2025-26

NCERT Solutions for Class 12 Chemistry Chapter Chapter 7 Alcohol Phenol and Ether

NCERT Solutions ForClass 12 Chemistry Chapter Chapter 8 Aldehydes Ketones And Carboxylic Acids

JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

