$N{H_4}OH$ is a weak base because:
A.It is completely ionised
B.It has a low vapour density
C.It has a low density
D.It is only partially ionised
Answer
267.6k+ views
Hint: To answer this question, you should recall the concept of ionisation of weak bases. Any base which is called a weak base is dependent on the value of ionization constant ${\text{(}}{{\text{K}}_{\text{b}}}{\text{)}}$. ${{\text{K}}_{\text{b}}}$ of any base helps determine how completely a base dissociates into its component ions in water.
Complete step by step answer:
We know that $N{H_4}OH$ dissociates in water as \[N{H_3} + {H_2}O \to N{H_4}^ + + O{H^ - }\]. This reaction has \[{{\text{K}}_{\text{b}}} = 1.8 \times {10^{ - 5}}\]. You can notice that the value of ${{\text{K}}_{\text{b}}}$ is quite small, meaning that very little ammonium and hydroxide forms in the solution.
In other words, the concentration of $O{H^ - }$ is much smaller than the nominal ammonia or “ammonium hydroxide” concentration. That’s why it is a weak base.
Another point to be noted is that the relative sizes of $N{H_4}^ + $ and hydroxide ions are comparable. This leads to a strong bond between ammonium ion and Hydroxide ion. As a result, when dissolved in water, $N{H_4}OH$ doesn't dissociate completely leading to its weak basic character. Hence, $N{H_4}OH$ is a weak base because it partially dissociates into $N{H_4}^ + $and $O{H^ - }$ ions in aqueous solutions and the amount of $O{H^ - }$ ions produced is low as it is partially ionised.
Therefore, we can conclude that the correct answer to this question is option D.
Note: You should remember the difference between strong bases and weak bases: a strong base is a base that is $100\% $ ionized in solution but if it is less than $100\% $ ionized in solution, it is a weak base. There are very few strong bases and certain salts will also affect the acidity or basicity of aqueous solutions because some of the ions will undergo hydrolysis. The general rule is that salts with ions that are part of strong acids or bases will not hydrolyse, while salts with ions that are part of weak acids or bases will hydrolyse.
Complete step by step answer:
We know that $N{H_4}OH$ dissociates in water as \[N{H_3} + {H_2}O \to N{H_4}^ + + O{H^ - }\]. This reaction has \[{{\text{K}}_{\text{b}}} = 1.8 \times {10^{ - 5}}\]. You can notice that the value of ${{\text{K}}_{\text{b}}}$ is quite small, meaning that very little ammonium and hydroxide forms in the solution.
In other words, the concentration of $O{H^ - }$ is much smaller than the nominal ammonia or “ammonium hydroxide” concentration. That’s why it is a weak base.
Another point to be noted is that the relative sizes of $N{H_4}^ + $ and hydroxide ions are comparable. This leads to a strong bond between ammonium ion and Hydroxide ion. As a result, when dissolved in water, $N{H_4}OH$ doesn't dissociate completely leading to its weak basic character. Hence, $N{H_4}OH$ is a weak base because it partially dissociates into $N{H_4}^ + $and $O{H^ - }$ ions in aqueous solutions and the amount of $O{H^ - }$ ions produced is low as it is partially ionised.
Therefore, we can conclude that the correct answer to this question is option D.
Note: You should remember the difference between strong bases and weak bases: a strong base is a base that is $100\% $ ionized in solution but if it is less than $100\% $ ionized in solution, it is a weak base. There are very few strong bases and certain salts will also affect the acidity or basicity of aqueous solutions because some of the ions will undergo hydrolysis. The general rule is that salts with ions that are part of strong acids or bases will not hydrolyse, while salts with ions that are part of weak acids or bases will hydrolyse.
Recently Updated Pages
Disproportionation Reaction: Definition, Example & JEE Guide

Hess Law of Constant Heat Summation: Definition, Formula & Applications

Algebra Made Easy: Step-by-Step Guide for Students

JEE Isolation, Preparation and Properties of Non-metals Important Concepts and Tips for Exam Preparation

JEE Energetics Important Concepts and Tips for Exam Preparation

Chemical Properties of Hydrogen - Important Concepts for JEE Exam Preparation

Trending doubts
JEE Main 2026: Exam Dates, Session 2 Updates, City Slip, Admit Card & Latest News

JEE Main Participating Colleges 2026 - A Complete List of Top Colleges

Understanding the Electric Field of a Uniformly Charged Ring

Derivation of Equation of Trajectory Explained for Students

Understanding Atomic Structure for Beginners

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
JEE Advanced 2026 Notification Out with Exam Date, Registration (Extended), Syllabus and More

JEE Advanced Percentile vs Marks 2026: JEE Main Cutoff, AIR & IIT Admission Guide

JEE Advanced 2026 Marks vs Rank: Estimate IIT Rank from Your Score

JEE Advanced Weightage Chapter Wise 2026 for Physics, Chemistry, and Mathematics

NCERT Solutions For Class 11 Chemistry In Hindi Chapter 1 Some Basic Concepts Of Chemistry - 2025-26

Understanding Electromagnetic Waves and Their Importance

