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# Magnifying power of an astronomical telescope is 'M.P'. If the focal length of objective is doubled, then the magnifying power for normal adjustment will become(A) $2 \mathrm{M.P}$(B) $\dfrac{\text { M.P }}{2}$(C) $3 \mathrm{M.P}$(D) $\dfrac{3 \mathrm{M.P}}{2}$

Last updated date: 13th Jun 2024
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Hint: We know that magnification is the ability to make small objects seem larger, such as making a microscopic organism visible. Resolution is the ability to distinguish two objects from each other. When the image formed is virtual and erect, magnification is positive. And, when the image formed is real and inverted, magnification is negative. The underlying principle of a microscope is that lenses refract light which allows for magnification. Refraction occurs when light travels through an area of space that has a changing index of refraction.

The magnifying power or M.P of the reflecting telescope is $\dfrac{\mathrm{f}_{0}}{\mathrm{f}_{\mathrm{e}}} .$
If the focal length of the eye-piece is halved, then its magnifying power $\mathrm{m}^{\prime}\left(\dfrac{\mathrm{f}_{0} \times 2}{\mathrm{f}_{\mathrm{e}}}\right)$ is 2 M.P.