Answer
64.8k+ views
Hint the maximum static friction that a body can exert on the other body in contact with it, is called limiting friction. This limiting friction is proportional to normal contact force between the two bodies. We can write,
\[{f_{\max }} = {\mu _s}{\rm N}\]
Where, \[{f_{\max }}\] is the maximum possible of static friction.
And, ${\rm N}$ is normal force.
Complete Step by step solution
The amount of friction that can be applied between two surfaces is limited and if the forces acting on the body are made sufficiently great; the motion will occur. Hence, we can define limiting friction as the maximum value of static friction that comes into play when the body is just at the point of sliding over the surface of another body. Limiting friction is the product of normal force and coefficient of limiting friction. Mathematically, this is represented as
\[{f_{\max }} = {\mu _s}{\rm N}\]
Here, ${\mu _s}$ is constant of proportionality and is called the coefficient of static friction and its value depends on the material and roughness of the two surfaces in contact. In general, ${\mu _s}$ is slightly greater than ${\mu _k}$ i.e., coefficient of kinetic friction.
Now as long as the normal force is constant, the maximum possible friction does not depend on the area of the area of the surfaces in contact.
Once again, we emphasize that \[{\mu _s}{\rm N}\] is the maximum possible force of static friction that acts between the bodies. The actual force of static friction may be smaller than \[{\mu _s}{\rm N}\] and its value depends on the other forces acting on the body. The magnitude of frictional force is equal to that required to keep the body at relative rest. Thus,
${f_s} \leqslant {f_{\max }} = {\mu _s}{\rm N}$
The limiting friction is always opposite to the motion of the object.
Hence option (A) is correct.
Note Static friction is a self-adjusting force because it comes into play when the body is lying over the surface of another body without any motion. If we have not applied any force on a body to move the body, the frictional force also becomes zero. If we start applying force, with the applied force, the frictional force also starts increasing. This happens until the applied force is less than limiting frictional force. When that body overcomes the force of static friction, the maximum value of static friction is reached -which is known as limiting friction. After the limiting friction, the frictional force is not going to increase further. At this stage, the object moves overcoming the frictional force which is at a constant value. This is called kinetic friction.
\[{f_{\max }} = {\mu _s}{\rm N}\]
Where, \[{f_{\max }}\] is the maximum possible of static friction.
And, ${\rm N}$ is normal force.
Complete Step by step solution
The amount of friction that can be applied between two surfaces is limited and if the forces acting on the body are made sufficiently great; the motion will occur. Hence, we can define limiting friction as the maximum value of static friction that comes into play when the body is just at the point of sliding over the surface of another body. Limiting friction is the product of normal force and coefficient of limiting friction. Mathematically, this is represented as
\[{f_{\max }} = {\mu _s}{\rm N}\]
Here, ${\mu _s}$ is constant of proportionality and is called the coefficient of static friction and its value depends on the material and roughness of the two surfaces in contact. In general, ${\mu _s}$ is slightly greater than ${\mu _k}$ i.e., coefficient of kinetic friction.
Now as long as the normal force is constant, the maximum possible friction does not depend on the area of the area of the surfaces in contact.
Once again, we emphasize that \[{\mu _s}{\rm N}\] is the maximum possible force of static friction that acts between the bodies. The actual force of static friction may be smaller than \[{\mu _s}{\rm N}\] and its value depends on the other forces acting on the body. The magnitude of frictional force is equal to that required to keep the body at relative rest. Thus,
${f_s} \leqslant {f_{\max }} = {\mu _s}{\rm N}$
The limiting friction is always opposite to the motion of the object.
Hence option (A) is correct.
Note Static friction is a self-adjusting force because it comes into play when the body is lying over the surface of another body without any motion. If we have not applied any force on a body to move the body, the frictional force also becomes zero. If we start applying force, with the applied force, the frictional force also starts increasing. This happens until the applied force is less than limiting frictional force. When that body overcomes the force of static friction, the maximum value of static friction is reached -which is known as limiting friction. After the limiting friction, the frictional force is not going to increase further. At this stage, the object moves overcoming the frictional force which is at a constant value. This is called kinetic friction.
Recently Updated Pages
Write a composition in approximately 450 500 words class 10 english JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Arrange the sentences P Q R between S1 and S5 such class 10 english JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
What is the common property of the oxides CONO and class 10 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
What happens when dilute hydrochloric acid is added class 10 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
If four points A63B 35C4 2 and Dx3x are given in such class 10 maths JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
The area of square inscribed in a circle of diameter class 10 maths JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Other Pages
Excluding stoppages the speed of a bus is 54 kmph and class 11 maths JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
In the ground state an element has 13 electrons in class 11 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Electric field due to uniformly charged sphere class 12 physics JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
A boat takes 2 hours to go 8 km and come back to a class 11 physics JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
According to classical free electron theory A There class 11 physics JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Differentiate between homogeneous and heterogeneous class 12 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)