
Lateral displacement of the emergent ray of light increases with
(A) Increases in angle of incidence
(B) Decreases in refractive index of medium
(C) Increases in the wavelength of light
(D) None
Answer
137.4k+ views
Hint: First of all define the term “lateral displacement” and explain it. Write the formula of lateral displacement and then relate the term. In refraction, emergent ray is parallel to the incident ray but in actual it appears slightly shifted and this shift in the position of the emergent ray as compared to the incident ray is known as lateral displacement.
Complete answer:
Lateral displacement is the perpendicular distance between the incident ray and the emergent ray. The formula of lateral displacement is given by
${{S = }}\dfrac{{{t}}}{{{{cos r}}}}{{sin (i - r)}}$
Where S = lateral shift
t = thickness of the medium
i = angle of incidence
r = angle of refraction
So, the lateral displacement depends upon the angle of incidence, the angle of refraction along with the thickness of the medium.
As per the given options, lateral displacement doesn’t depend upon neither refractive index nor wavelength of medium.
Thus, lateral displacement of the emergent ray of light increases with increases in angle of incidence.
Therefore, option (A) is the correct choice.
Note: Refractive Index or index of refraction) is defined as the ratio of the speed of light in a vacuum to the speed of light in a second medium of greater density. Refractive index is represented by the term ${{n}}$. The refractive index depends upon the wavelength, this causes white light to split into constituent colours on refraction. This phenomenon is called dispersion. For visible light, the term “normal dispersion” means that the refractive index is higher for blue coloured light than for red light colour.
Complete answer:
Lateral displacement is the perpendicular distance between the incident ray and the emergent ray. The formula of lateral displacement is given by
${{S = }}\dfrac{{{t}}}{{{{cos r}}}}{{sin (i - r)}}$
Where S = lateral shift
t = thickness of the medium
i = angle of incidence
r = angle of refraction
So, the lateral displacement depends upon the angle of incidence, the angle of refraction along with the thickness of the medium.
As per the given options, lateral displacement doesn’t depend upon neither refractive index nor wavelength of medium.
Thus, lateral displacement of the emergent ray of light increases with increases in angle of incidence.
Therefore, option (A) is the correct choice.
Note: Refractive Index or index of refraction) is defined as the ratio of the speed of light in a vacuum to the speed of light in a second medium of greater density. Refractive index is represented by the term ${{n}}$. The refractive index depends upon the wavelength, this causes white light to split into constituent colours on refraction. This phenomenon is called dispersion. For visible light, the term “normal dispersion” means that the refractive index is higher for blue coloured light than for red light colour.
Recently Updated Pages
COM of Semicircular Ring Important Concepts and Tips for JEE

Geostationary Satellites and Geosynchronous Satellites for JEE

Current Loop as Magnetic Dipole Important Concepts for JEE

Electromagnetic Waves Chapter for JEE Main Physics

Structure of Atom: Key Models, Subatomic Particles, and Quantum Numbers

JEE Main 2023 January 25 Shift 1 Question Paper with Answer Key

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility, & More

JEE Main 2025: Derivation of Equation of Trajectory in Physics

Learn About Angle Of Deviation In Prism: JEE Main Physics 2025

Degree of Dissociation and Its Formula With Solved Example for JEE

Physics Average Value and RMS Value JEE Main 2025

Formula for number of images formed by two plane mirrors class 12 physics JEE_Main

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Dual Nature of Radiation and Matter Class 12 Notes: CBSE Physics Chapter 11

Electric field due to uniformly charged sphere class 12 physics JEE_Main

Collision - Important Concepts and Tips for JEE

Electric Field Due to Uniformly Charged Ring for JEE Main 2025 - Formula and Derivation

Charging and Discharging of Capacitor
