
In the electrochemical series, ions are arranged in an increasing order of discharge potentials.
(A) True
(B) False
Answer
224.7k+ views
Hint: The electrochemical series is the arrangement of various electrode systems in the increasing order of their standard reduction potentials. An electrode with higher standard reduction potential has a high tendency to get reduced, thus the ion will have lower discharge potential.
Complete step by step solution:
Discharge potential is the ability of an ion to get discharged at the electrodes.
The discharge potential of any ion mainly depends on three factors:
(1) The relative position of ions in the electrochemical series.
(2) The relative concentration of ions. The ions with higher concentration will discharge easily.
(3) The nature of the electrodes
Reduction potential is the tendency of the electrodes to accept electrons and as a result it gets reduced.
The cations will get discharged when they gain electrons (or get reduced). The cations with high reduction potential will get discharged easily and will have lower discharge potential. Those which have low reduction potential will have higher discharge potential.
Similarly, anions will get discharged when they lose electrons. Hence anions with higher oxidation potential will have lower discharge potential and those with lower oxidation potential will have lower discharge potential.
Thus discharge potential depends on reduction or oxidation potential.
The cations that have a lower position in the electrochemical series are preferentially discharged and the anions that have a higher position in the electrochemical series are preferentially discharged.
Therefore, in the electrochemical series ions are arranged in an increasing order of discharge potentials.
Hence, option (A) is the correct answer.
Note: At cathode, the reaction involving higher \[{E^0}\] value is preferred i.e., it will be reduced. The increasing order of discharge of few cations at cathode is: ${K^ + },\,C{a^ + },\,N{a^ + },\,M{g^ + },\,A{l^ + },\,Z{n^ + },\,F{e^ + },\,{H^ + },\,C{u^ + },\,A{g^ + }$
At anode, the reaction involving lower \[{E^0}\]value is preferred i.e., it will be oxidised. The increasing order of discharge of few anions at anode is: $SO_4^{2 - },\,NO_3^ - ,\,O{H^ - },\,C{l^ - },\,B{r^ - },\,{H^ - }$
Irrespective of the position of the ions in the electrochemical series there is a tendency to discharge the ions which has a higher concentration.
Complete step by step solution:
Discharge potential is the ability of an ion to get discharged at the electrodes.
The discharge potential of any ion mainly depends on three factors:
(1) The relative position of ions in the electrochemical series.
(2) The relative concentration of ions. The ions with higher concentration will discharge easily.
(3) The nature of the electrodes
Reduction potential is the tendency of the electrodes to accept electrons and as a result it gets reduced.
The cations will get discharged when they gain electrons (or get reduced). The cations with high reduction potential will get discharged easily and will have lower discharge potential. Those which have low reduction potential will have higher discharge potential.
Similarly, anions will get discharged when they lose electrons. Hence anions with higher oxidation potential will have lower discharge potential and those with lower oxidation potential will have lower discharge potential.
Thus discharge potential depends on reduction or oxidation potential.
The cations that have a lower position in the electrochemical series are preferentially discharged and the anions that have a higher position in the electrochemical series are preferentially discharged.
Therefore, in the electrochemical series ions are arranged in an increasing order of discharge potentials.
Hence, option (A) is the correct answer.
Note: At cathode, the reaction involving higher \[{E^0}\] value is preferred i.e., it will be reduced. The increasing order of discharge of few cations at cathode is: ${K^ + },\,C{a^ + },\,N{a^ + },\,M{g^ + },\,A{l^ + },\,Z{n^ + },\,F{e^ + },\,{H^ + },\,C{u^ + },\,A{g^ + }$
At anode, the reaction involving lower \[{E^0}\]value is preferred i.e., it will be oxidised. The increasing order of discharge of few anions at anode is: $SO_4^{2 - },\,NO_3^ - ,\,O{H^ - },\,C{l^ - },\,B{r^ - },\,{H^ - }$
Irrespective of the position of the ions in the electrochemical series there is a tendency to discharge the ions which has a higher concentration.
Recently Updated Pages
JEE Main 2026 Session 1 Correction Window Started: Check Dates, Edit Link & Fees

JEE Isolation, Preparation and Properties of Non-metals Important Concepts and Tips for Exam Preparation

Isoelectronic Definition in Chemistry: Meaning, Examples & Trends

Ionisation Energy and Ionisation Potential Explained

Iodoform Reactions - Important Concepts and Tips for JEE

Introduction to Dimensions: Understanding the Basics

Trending doubts
JEE Main 2026: City Intimation Slip and Exam Dates Released, Application Form Closed, Syllabus & Eligibility

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

Understanding the Angle of Deviation in a Prism

Hybridisation in Chemistry – Concept, Types & Applications

How to Convert a Galvanometer into an Ammeter or Voltmeter

Ideal and Non-Ideal Solutions Explained for Class 12 Chemistry

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Thermodynamics Class 11 Chemistry Chapter 5 CBSE Notes - 2025-26

Organic Chemistry Some Basic Principles And Techniques Class 11 Chemistry Chapter 8 CBSE Notes - 2025-26

Hydrocarbons Class 11 Chemistry Chapter 9 CBSE Notes - 2025-26

JEE Advanced 2026 - Exam Date (Released), Syllabus, Registration, Eligibility, Preparation, and More

JEE Advanced 2026 - Exam Date (Released), Syllabus, Registration, Eligibility, Preparation, and More

