Answer
64.8k+ views
Hint: To solve this problem, we have to compute the mechanism in which the communication happens in space and correspondingly, the speed of the channel used in the communication of the information.
Complete step by step solution:
Let us understand the mechanism of information transfer that happens across space.
The space communication consists of two major components: Transmitter and Receiver.
A transmitter encodes the information signal and modulates it to a high-wavelength radiation in the form of radio-waves or microwaves which are emitted.
The receiver catches this radiation and demodulates it and then, the message signal is received at the other end.
Thus, we see that the radio-waves or microwaves are used for space communication purposes.
Radio wave is the part of the electromagnetic radiation spectrum whose wavelength is longer than infrared light. The radio waves have a wide range of frequencies up to $30GHz - 300GHz$. Hence, its corresponding wavelength ranges from as low as 1 mm to almost $10,000km$. This huge range of wavelength is employed for communications over very large distances across ground-to-ground or ground-to-air.
Since the radio-waves belong to the spectrum of electromagnetic radiation, the spectrum of electromagnetic radiation have a constant velocity and the value of velocity is given by:
$c = 3 \times {10^8}m{s^{ - 1}}$
Now, the distance to be travelled by the radiowaves is equal to –
$\Rightarrow d = 100km = 100 \times {10^3}m$
The time taken to travel is obtained by dividing the distance to be travelled by the speed of light.
$\Rightarrow t = \dfrac{d}{s} = \dfrac{{100 \times {{10}^3}}}{{3 \times {{10}^8}}} = 33.33 \times {10^{ - 5}}\sec $
$\therefore t = 0.00033\sec $
Hence, the correct option is Option D.
Note: Here, we have to consider the fact that the velocity of light remains constant in vacuum or any other medium. This gives us the relation that the distance covered is directly proportional to the time taken. This means that if the distances are too long, the time taken for the information signal to reach will be very large.
Complete step by step solution:
Let us understand the mechanism of information transfer that happens across space.
The space communication consists of two major components: Transmitter and Receiver.
A transmitter encodes the information signal and modulates it to a high-wavelength radiation in the form of radio-waves or microwaves which are emitted.
The receiver catches this radiation and demodulates it and then, the message signal is received at the other end.
Thus, we see that the radio-waves or microwaves are used for space communication purposes.
Radio wave is the part of the electromagnetic radiation spectrum whose wavelength is longer than infrared light. The radio waves have a wide range of frequencies up to $30GHz - 300GHz$. Hence, its corresponding wavelength ranges from as low as 1 mm to almost $10,000km$. This huge range of wavelength is employed for communications over very large distances across ground-to-ground or ground-to-air.
Since the radio-waves belong to the spectrum of electromagnetic radiation, the spectrum of electromagnetic radiation have a constant velocity and the value of velocity is given by:
$c = 3 \times {10^8}m{s^{ - 1}}$
Now, the distance to be travelled by the radiowaves is equal to –
$\Rightarrow d = 100km = 100 \times {10^3}m$
The time taken to travel is obtained by dividing the distance to be travelled by the speed of light.
$\Rightarrow t = \dfrac{d}{s} = \dfrac{{100 \times {{10}^3}}}{{3 \times {{10}^8}}} = 33.33 \times {10^{ - 5}}\sec $
$\therefore t = 0.00033\sec $
Hence, the correct option is Option D.
Note: Here, we have to consider the fact that the velocity of light remains constant in vacuum or any other medium. This gives us the relation that the distance covered is directly proportional to the time taken. This means that if the distances are too long, the time taken for the information signal to reach will be very large.
Recently Updated Pages
Write a composition in approximately 450 500 words class 10 english JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Arrange the sentences P Q R between S1 and S5 such class 10 english JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
What is the common property of the oxides CONO and class 10 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
What happens when dilute hydrochloric acid is added class 10 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
If four points A63B 35C4 2 and Dx3x are given in such class 10 maths JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
The area of square inscribed in a circle of diameter class 10 maths JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Other Pages
A boat takes 2 hours to go 8 km and come back to a class 11 physics JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Electric field due to uniformly charged sphere class 12 physics JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
In the ground state an element has 13 electrons in class 11 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
According to classical free electron theory A There class 11 physics JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Differentiate between homogeneous and heterogeneous class 12 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Excluding stoppages the speed of a bus is 54 kmph and class 11 maths JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)