
In solvents like$DMSO$, acetonitrile, ${{F}^{-}}$ ion of dissolved $NaF$ is more reactive than in methyl alcohol. Explain
A. $C{{H}_{3}}OH$ is more polar than $DMSO$ and $C{{H}_{3}}CN$
B. $C{{H}_{3}}OH$ is less polar than $DMSO$ and $C{{H}_{3}}CN$
C. Unsolved ${{F}^{-}}$ ion is $DMSO$ or $C{{H}_{3}}CN$ acts more effectively as nucleophile
D. $-OH$ group is better leaving group than ${{F}^{-}}$ ion
Answer
124.2k+ views
Hint: In the methyl alcohol ${{F}^{-}}$ion is solvated whereas in the solvents like $DMSO$ and acetonitrile this ${{F}^{-}}$ion of dissolved $NaF$is not solvated. Analyze the above line and find the activity of the${{F}^{-}}$ion in both the cases and find out the correct explanation from the given above options.
Complete step by step answer:
We know that when we try to dissolve the compound $NaF$ in methyl alcohol the dissolved ${{F}^{-}}$ ions are get solvated in it, that is the ${{F}^{-}}$ ions are get solvated in methyl alcohol whereas in case of the solvents like $DMSO$ and acetonitrile these ${{F}^{-}}$ ion of dissolved $NaF$ are not solvated and so these ions are free in the solvent. Due to the presence of the free ${{F}^{-}}$ ions in the solvent which are not solvated, these act as more efficiently as nucleophiles.
A nucleophile is a chemical species that donates an electron pair to form a chemical bond in a reaction to reaction. All molecules or ions with a free pair of electrons or at least one \[\pi \] bond can act as nucleophiles. Because nucleophiles donate electrons, they are by definition Lewis bases.
Since we found that the unsolvated ${{F}^{-}}$ ions more efficiently act as a nucleophile and hence option (C) is the correct answer.
Note: The solvent $DMSO$ is dimethyl sulfoxide which is having the chemical formula \[{{\left( C{{H}_{3}} \right)}_{2}}SO\] is an important polar aprotic solvent that dissolves both polar and non polar compounds and is miscible in a wide range of organic solvents as well as water, where is the chemical formula of the acetonitrile is \[C{{H}_{3}}-CN\] used as polar aprotic solvent in the organic synthesis and in the purification of the butadiene.
Complete step by step answer:
We know that when we try to dissolve the compound $NaF$ in methyl alcohol the dissolved ${{F}^{-}}$ ions are get solvated in it, that is the ${{F}^{-}}$ ions are get solvated in methyl alcohol whereas in case of the solvents like $DMSO$ and acetonitrile these ${{F}^{-}}$ ion of dissolved $NaF$ are not solvated and so these ions are free in the solvent. Due to the presence of the free ${{F}^{-}}$ ions in the solvent which are not solvated, these act as more efficiently as nucleophiles.
A nucleophile is a chemical species that donates an electron pair to form a chemical bond in a reaction to reaction. All molecules or ions with a free pair of electrons or at least one \[\pi \] bond can act as nucleophiles. Because nucleophiles donate electrons, they are by definition Lewis bases.
Since we found that the unsolvated ${{F}^{-}}$ ions more efficiently act as a nucleophile and hence option (C) is the correct answer.
Note: The solvent $DMSO$ is dimethyl sulfoxide which is having the chemical formula \[{{\left( C{{H}_{3}} \right)}_{2}}SO\] is an important polar aprotic solvent that dissolves both polar and non polar compounds and is miscible in a wide range of organic solvents as well as water, where is the chemical formula of the acetonitrile is \[C{{H}_{3}}-CN\] used as polar aprotic solvent in the organic synthesis and in the purification of the butadiene.
Recently Updated Pages
Classification of Drugs Based on Pharmacological Effect, Drug Action

Types of Solutions - Solution in Chemistry

Difference Between Alcohol and Phenol

JEE Main Participating Colleges 2024 - A Complete List of Top Colleges

JEE Main Maths Paper Pattern 2025 – Marking, Sections & Tips

Sign up for JEE Main 2025 Live Classes - Vedantu

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility & More

JEE Main Exam Marking Scheme: Detailed Breakdown of Marks and Negative Marking

JEE Main 2023 January 24 Shift 2 Question Paper with Answer Keys & Solutions

Learn About Angle Of Deviation In Prism: JEE Main Physics 2025

JEE Main 2025: Conversion of Galvanometer Into Ammeter And Voltmeter in Physics

JEE Main Login 2045: Step-by-Step Instructions and Details

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

NCERT Solutions for Class 12 Chemistry Chapter 6 Haloalkanes and Haloarenes

NCERT Solutions for Class 12 Chemistry Chapter 1 Solutions

NCERT Solutions for Class 12 Chemistry Chapter 2 Electrochemistry

NCERT Solutions for Class 12 Chemistry Chapter 7 Alcohol Phenol and Ether

NCERT Solutions for Class 12 Chemistry Chapter 8 Aldehydes Ketones and Carboxylic Acids
