Answer
Verified
38.1k+ views
Hint: In order to find the solution to this question, we should know about the concept of the probability that is, the ratio of favorable outcomes to the total number of outcomes of any event. Mathematically, we can write, the probability of an event \[=\dfrac{\text{Favorable outcomes}}{\text{Total outcomes}}.\] By using this concept, we can find the answer to this question.
Complete step-by-step answer:
In this question, we have been asked to find the probability of Aayushi scoring 100 out of 100. To solve this question, we should know about the concept of probability, that is, the ratio of the favorable outcomes to the total number of outcomes. Therefore, we can say,
\[\text{Probability of an event}=\dfrac{\text{Favorable outcomes}}{\text{Total outcomes}}\]
Now, we have been given that the maximum marks Aayushi can score is 100. But we know that Aayushi can also have a score of 0 marks, 1 mark, 2 marks, 3 marks, ….., 100 marks, that is, there are 101 possibilities. So, we can say the total number of favorable outcomes is 101. Now, we have been given that we have to find the probability to get 100 marks. So, we have only 1 possible mark, which is 100 marks. Therefore, we can say that there is 1 favorable outcome. So, we can say the portability of Aayushi scoring 100 out of 100 marks is
\[\text{Probability Aayushi scoring 100 out of 100 marks}=\dfrac{1}{101}\]
Hence, we can say that the probability of Aayushi scoring 100 out of 100 marks is \[\dfrac{1}{101}.\] Therefore, we can say option (d) is the right answer.
Note: While solving this question, the possible mistake one can make is counting the total number of outcomes as 100 by not including 0 marks as the outcome. But we know that in an exam, one can also score 0 marks. Therefore, there are 101 outcomes in total.
Complete step-by-step answer:
In this question, we have been asked to find the probability of Aayushi scoring 100 out of 100. To solve this question, we should know about the concept of probability, that is, the ratio of the favorable outcomes to the total number of outcomes. Therefore, we can say,
\[\text{Probability of an event}=\dfrac{\text{Favorable outcomes}}{\text{Total outcomes}}\]
Now, we have been given that the maximum marks Aayushi can score is 100. But we know that Aayushi can also have a score of 0 marks, 1 mark, 2 marks, 3 marks, ….., 100 marks, that is, there are 101 possibilities. So, we can say the total number of favorable outcomes is 101. Now, we have been given that we have to find the probability to get 100 marks. So, we have only 1 possible mark, which is 100 marks. Therefore, we can say that there is 1 favorable outcome. So, we can say the portability of Aayushi scoring 100 out of 100 marks is
\[\text{Probability Aayushi scoring 100 out of 100 marks}=\dfrac{1}{101}\]
Hence, we can say that the probability of Aayushi scoring 100 out of 100 marks is \[\dfrac{1}{101}.\] Therefore, we can say option (d) is the right answer.
Note: While solving this question, the possible mistake one can make is counting the total number of outcomes as 100 by not including 0 marks as the outcome. But we know that in an exam, one can also score 0 marks. Therefore, there are 101 outcomes in total.
Recently Updated Pages
To get a maximum current in an external resistance class 1 physics JEE_Main
f a body travels with constant acceleration which of class 1 physics JEE_Main
If the beams of electrons and protons move parallel class 1 physics JEE_Main
Let f be a twice differentiable such that fleft x rightfleft class 11 maths JEE_Main
Find the points of intersection of the tangents at class 11 maths JEE_Main
For the two circles x2+y216 and x2+y22y0 there isare class 11 maths JEE_Main
Other Pages
How many grams of concentrated nitric acid solution class 11 chemistry JEE_Main
Electric field due to uniformly charged sphere class 12 physics JEE_Main
The mole fraction of the solute in a 1 molal aqueous class 11 chemistry JEE_Main
Dissolving 120g of urea molwt60 in 1000g of water gave class 11 chemistry JEE_Main
when an object Is placed at a distance of 60 cm from class 12 physics JEE_Main
Differentiate between homogeneous and heterogeneous class 12 chemistry JEE_Main