
In graphite, electrons are:
(A) Localized on each carbon atom
(B) Spread out between the sheets
(C) localized on every third carbon atom
(D) present in antibonding orbital
Answer
219.9k+ views
Hint: Graphite is an allotrope of carbon element. When the same element is present in more than one form they are called allotropes.
Carbon is present in three forms in nature i.e. Diamond, Graphite and fullerene.
Complete step by step answer:
Carbon atom in graphite present in$s{p^2}$ hybridized state.
Electronic configuration of C is$ - 1{s^2}2{s^2}2p{x^1}2p{y^1}$
At ground state =

At excited state =

In graphite $1s$ and $2p$ orbital hybridize and form $s{p^2}$ hybridized orbital and one orbital remains hybridized.
Hybridized state=

Three hybrid orbits contain one electron each.
These electrons form a covalent bond with the hybrid orbital of other C-atoms.
Each carbon atom forms a covalent bond with another carbon atom. They form interlinked six membered rings of carbon atoms. The remaining half filled unhybridized $2{p^2}$orbital is used for$\pi $bonding. So that layers of carbon atoms i.e. graphite is formed.

Graphite has delocalized molecular orbital and delocalized electrons and is free to move in delocalized molecular orbital.
Therefore, electrons get spread between the sheets.
Therefore, from the above explanation, the correct option is B
Additional information:
Graphite is a good conductor of heat and electricity. The layer of carbon atoms in graphite can slide over another layer. So it is used in lubricants for reducing friction.
Note: Graphite forms hexagonal layers and these layers of carbon atom are held together by weak Van der Waals forces of attraction.
Carbon atoms have a unique property to link with itself called catenation. Due to this property allotropes of carbon form giant molecules.
Carbon is present in three forms in nature i.e. Diamond, Graphite and fullerene.
Complete step by step answer:
Carbon atom in graphite present in$s{p^2}$ hybridized state.
Electronic configuration of C is$ - 1{s^2}2{s^2}2p{x^1}2p{y^1}$
At ground state =

At excited state =

In graphite $1s$ and $2p$ orbital hybridize and form $s{p^2}$ hybridized orbital and one orbital remains hybridized.
Hybridized state=

Three hybrid orbits contain one electron each.
These electrons form a covalent bond with the hybrid orbital of other C-atoms.
Each carbon atom forms a covalent bond with another carbon atom. They form interlinked six membered rings of carbon atoms. The remaining half filled unhybridized $2{p^2}$orbital is used for$\pi $bonding. So that layers of carbon atoms i.e. graphite is formed.

Graphite has delocalized molecular orbital and delocalized electrons and is free to move in delocalized molecular orbital.
Therefore, electrons get spread between the sheets.
Therefore, from the above explanation, the correct option is B
Additional information:
Graphite is a good conductor of heat and electricity. The layer of carbon atoms in graphite can slide over another layer. So it is used in lubricants for reducing friction.
Note: Graphite forms hexagonal layers and these layers of carbon atom are held together by weak Van der Waals forces of attraction.
Carbon atoms have a unique property to link with itself called catenation. Due to this property allotropes of carbon form giant molecules.
Recently Updated Pages
Electricity and Magnetism Explained: Key Concepts & Applications

JEE Energetics Important Concepts and Tips for Exam Preparation

JEE Isolation, Preparation and Properties of Non-metals Important Concepts and Tips for Exam Preparation

JEE Main 2021 July 25 Shift 1 Question Paper with Answer Key

JEE Main 2021 July 22 Shift 2 Question Paper with Answer Key

States of Matter Chapter For JEE Main Chemistry

Trending doubts
Understanding Atomic Structure for Beginners

Understanding Centrifugal Force in Physics

JEE Main Marking Scheme 2026- Paper-Wise Marks Distribution and Negative Marking Details

Understanding Electromagnetic Waves and Their Importance

Understanding Entropy Changes in Different Processes

Common Ion Effect: Concept, Applications, and Problem-Solving

Other Pages
NCERT Solutions For Class 12 Chemistry Chapter 9 Amines

Understanding Excess Pressure Inside a Liquid Drop

Test for Phenolic Group

Understanding Geostationary and Geosynchronous Satellites

NCERT Solutions For Class 12 Chemistry Chapter 2 Chapter 2 Solutions Hindi Medium in Hindi - 2025-26

NCERT Solutions for Class 12 Chemistry Chapter 2 Electrochemistry

