
If \[x\] is measured in degrees, then \[\dfrac{d}{{dx}}(\cos x)\] is equal to
A. \[ - \sin x\]
B. \[ - (\dfrac{{180}}{\pi })\sin x\]
C. \[ - (\dfrac{\pi }{{180}})\sin x\]
D. \[\sin x\]
Answer
232.8k+ views
Hint: First we have to convert degree to radian. Derivative of a trigonometric function in degree does not exist. Then we will apply the formula \[\dfrac{d}{{dx}}\left( {\cos x} \right) = - \sin x\]
Formula Used: To the covert degree to radian, we have the formula \[{180^ \circ } = {\pi ^c}\]. \[\dfrac{d}{{dx}}(\cos x) = - \sin x\], where x is measured in radian. We can write \[\dfrac{{dy}}{{dx}} = \dfrac{{dy}}{{dz}}.\dfrac{{dz}}{{dx}}\] where y is a function of z and z is a function of x. This is called Chain Rule. Using this rule, we have \[\dfrac{d}{{dx}}(\cos y) = \dfrac{d}{{dy}}(\cos y)\dfrac{{dy}}{{dx}}\]
Complete step-by-step solution:
Here, x is measured in degrees. First, we have to convert the degree to radian. Derivative of trigonometric function in degree does not exist. Only the derivative of the trigonometric function in radian exists.
Therefore, \[{180^ \circ } = {\pi ^c}\]
or, \[{1^ \circ } = \dfrac{{{\pi ^c}}}{{180}}\]
or, \[{x^ \circ } = \dfrac{\pi }{{180}}{x^c}\]
Therefore,
\[\dfrac{d}{{dx}}(\cos {x^ \circ }) = \dfrac{d}{{dx}}(\cos \dfrac{{\pi {x^c}}}{{180}})\]
Let \[y = \dfrac{{\pi x}}{{180}}\]
\[\dfrac{d}{{dx}}(\cos y) = \dfrac{d}{{dy}}(\cos y)\dfrac{{dy}}{{dx}}\] [Using Chain Rule]
\[ = ( - \sin y)\dfrac{d}{{dx}}(\dfrac{{\pi x}}{{180}})\]
\[ = - \sin y \times \dfrac{\pi }{{180}} \times \dfrac{d}{{dx}}(x)\]
\[ = - \sin y \times \dfrac{\pi }{{180}} \times 1\]
\[ = \dfrac{\pi }{{180}} \times - \sin y\]
\[ = - \dfrac{\pi }{{180}}\sin (\dfrac{{\pi x}}{{180}})\]
Hence, option C. is correct.
Note: Students often mistake not to convert degree to radian. They only take derivatives and find the relevant option to choose the correct answer. They do not check whether it is in degree form or radian form. So, after getting the question, you have to notice carefully the question that is given in either degree form or radian form. If it is in radian form then you don’t convert. But if it is in degree form then you must convert it to radian form using the above formula and then take the derivative using the Chain Rule. If there is not mentioned anything in question then you should know that it is in radian form.
Formula Used: To the covert degree to radian, we have the formula \[{180^ \circ } = {\pi ^c}\]. \[\dfrac{d}{{dx}}(\cos x) = - \sin x\], where x is measured in radian. We can write \[\dfrac{{dy}}{{dx}} = \dfrac{{dy}}{{dz}}.\dfrac{{dz}}{{dx}}\] where y is a function of z and z is a function of x. This is called Chain Rule. Using this rule, we have \[\dfrac{d}{{dx}}(\cos y) = \dfrac{d}{{dy}}(\cos y)\dfrac{{dy}}{{dx}}\]
Complete step-by-step solution:
Here, x is measured in degrees. First, we have to convert the degree to radian. Derivative of trigonometric function in degree does not exist. Only the derivative of the trigonometric function in radian exists.
Therefore, \[{180^ \circ } = {\pi ^c}\]
or, \[{1^ \circ } = \dfrac{{{\pi ^c}}}{{180}}\]
or, \[{x^ \circ } = \dfrac{\pi }{{180}}{x^c}\]
Therefore,
\[\dfrac{d}{{dx}}(\cos {x^ \circ }) = \dfrac{d}{{dx}}(\cos \dfrac{{\pi {x^c}}}{{180}})\]
Let \[y = \dfrac{{\pi x}}{{180}}\]
\[\dfrac{d}{{dx}}(\cos y) = \dfrac{d}{{dy}}(\cos y)\dfrac{{dy}}{{dx}}\] [Using Chain Rule]
\[ = ( - \sin y)\dfrac{d}{{dx}}(\dfrac{{\pi x}}{{180}})\]
\[ = - \sin y \times \dfrac{\pi }{{180}} \times \dfrac{d}{{dx}}(x)\]
\[ = - \sin y \times \dfrac{\pi }{{180}} \times 1\]
\[ = \dfrac{\pi }{{180}} \times - \sin y\]
\[ = - \dfrac{\pi }{{180}}\sin (\dfrac{{\pi x}}{{180}})\]
Hence, option C. is correct.
Note: Students often mistake not to convert degree to radian. They only take derivatives and find the relevant option to choose the correct answer. They do not check whether it is in degree form or radian form. So, after getting the question, you have to notice carefully the question that is given in either degree form or radian form. If it is in radian form then you don’t convert. But if it is in degree form then you must convert it to radian form using the above formula and then take the derivative using the Chain Rule. If there is not mentioned anything in question then you should know that it is in radian form.
Recently Updated Pages
JEE Main 2023 April 6 Shift 1 Question Paper with Answer Key

JEE Main 2023 April 6 Shift 2 Question Paper with Answer Key

JEE Main 2023 (January 31 Evening Shift) Question Paper with Solutions [PDF]

JEE Main 2023 January 30 Shift 2 Question Paper with Answer Key

JEE Main 2023 January 25 Shift 1 Question Paper with Answer Key

JEE Main 2023 January 24 Shift 2 Question Paper with Answer Key

Trending doubts
JEE Main 2026: Session 2 Registration Open, City Intimation Slip, Exam Dates, Syllabus & Eligibility

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

Understanding the Angle of Deviation in a Prism

Hybridisation in Chemistry – Concept, Types & Applications

How to Convert a Galvanometer into an Ammeter or Voltmeter

Understanding the Electric Field of a Uniformly Charged Ring

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry

Derivation of Equation of Trajectory Explained for Students

Understanding Electromagnetic Waves and Their Importance

Understanding How a Current Loop Acts as a Magnetic Dipole

Understanding Average and RMS Value in Electrical Circuits

