
If \[x\] is measured in degrees, then \[\dfrac{d}{{dx}}(\cos x)\] is equal to
A. \[ - \sin x\]
B. \[ - (\dfrac{{180}}{\pi })\sin x\]
C. \[ - (\dfrac{\pi }{{180}})\sin x\]
D. \[\sin x\]
Answer
161.1k+ views
Hint: First we have to convert degree to radian. Derivative of a trigonometric function in degree does not exist. Then we will apply the formula \[\dfrac{d}{{dx}}\left( {\cos x} \right) = - \sin x\]
Formula Used: To the covert degree to radian, we have the formula \[{180^ \circ } = {\pi ^c}\]. \[\dfrac{d}{{dx}}(\cos x) = - \sin x\], where x is measured in radian. We can write \[\dfrac{{dy}}{{dx}} = \dfrac{{dy}}{{dz}}.\dfrac{{dz}}{{dx}}\] where y is a function of z and z is a function of x. This is called Chain Rule. Using this rule, we have \[\dfrac{d}{{dx}}(\cos y) = \dfrac{d}{{dy}}(\cos y)\dfrac{{dy}}{{dx}}\]
Complete step-by-step solution:
Here, x is measured in degrees. First, we have to convert the degree to radian. Derivative of trigonometric function in degree does not exist. Only the derivative of the trigonometric function in radian exists.
Therefore, \[{180^ \circ } = {\pi ^c}\]
or, \[{1^ \circ } = \dfrac{{{\pi ^c}}}{{180}}\]
or, \[{x^ \circ } = \dfrac{\pi }{{180}}{x^c}\]
Therefore,
\[\dfrac{d}{{dx}}(\cos {x^ \circ }) = \dfrac{d}{{dx}}(\cos \dfrac{{\pi {x^c}}}{{180}})\]
Let \[y = \dfrac{{\pi x}}{{180}}\]
\[\dfrac{d}{{dx}}(\cos y) = \dfrac{d}{{dy}}(\cos y)\dfrac{{dy}}{{dx}}\] [Using Chain Rule]
\[ = ( - \sin y)\dfrac{d}{{dx}}(\dfrac{{\pi x}}{{180}})\]
\[ = - \sin y \times \dfrac{\pi }{{180}} \times \dfrac{d}{{dx}}(x)\]
\[ = - \sin y \times \dfrac{\pi }{{180}} \times 1\]
\[ = \dfrac{\pi }{{180}} \times - \sin y\]
\[ = - \dfrac{\pi }{{180}}\sin (\dfrac{{\pi x}}{{180}})\]
Hence, option C. is correct.
Note: Students often mistake not to convert degree to radian. They only take derivatives and find the relevant option to choose the correct answer. They do not check whether it is in degree form or radian form. So, after getting the question, you have to notice carefully the question that is given in either degree form or radian form. If it is in radian form then you don’t convert. But if it is in degree form then you must convert it to radian form using the above formula and then take the derivative using the Chain Rule. If there is not mentioned anything in question then you should know that it is in radian form.
Formula Used: To the covert degree to radian, we have the formula \[{180^ \circ } = {\pi ^c}\]. \[\dfrac{d}{{dx}}(\cos x) = - \sin x\], where x is measured in radian. We can write \[\dfrac{{dy}}{{dx}} = \dfrac{{dy}}{{dz}}.\dfrac{{dz}}{{dx}}\] where y is a function of z and z is a function of x. This is called Chain Rule. Using this rule, we have \[\dfrac{d}{{dx}}(\cos y) = \dfrac{d}{{dy}}(\cos y)\dfrac{{dy}}{{dx}}\]
Complete step-by-step solution:
Here, x is measured in degrees. First, we have to convert the degree to radian. Derivative of trigonometric function in degree does not exist. Only the derivative of the trigonometric function in radian exists.
Therefore, \[{180^ \circ } = {\pi ^c}\]
or, \[{1^ \circ } = \dfrac{{{\pi ^c}}}{{180}}\]
or, \[{x^ \circ } = \dfrac{\pi }{{180}}{x^c}\]
Therefore,
\[\dfrac{d}{{dx}}(\cos {x^ \circ }) = \dfrac{d}{{dx}}(\cos \dfrac{{\pi {x^c}}}{{180}})\]
Let \[y = \dfrac{{\pi x}}{{180}}\]
\[\dfrac{d}{{dx}}(\cos y) = \dfrac{d}{{dy}}(\cos y)\dfrac{{dy}}{{dx}}\] [Using Chain Rule]
\[ = ( - \sin y)\dfrac{d}{{dx}}(\dfrac{{\pi x}}{{180}})\]
\[ = - \sin y \times \dfrac{\pi }{{180}} \times \dfrac{d}{{dx}}(x)\]
\[ = - \sin y \times \dfrac{\pi }{{180}} \times 1\]
\[ = \dfrac{\pi }{{180}} \times - \sin y\]
\[ = - \dfrac{\pi }{{180}}\sin (\dfrac{{\pi x}}{{180}})\]
Hence, option C. is correct.
Note: Students often mistake not to convert degree to radian. They only take derivatives and find the relevant option to choose the correct answer. They do not check whether it is in degree form or radian form. So, after getting the question, you have to notice carefully the question that is given in either degree form or radian form. If it is in radian form then you don’t convert. But if it is in degree form then you must convert it to radian form using the above formula and then take the derivative using the Chain Rule. If there is not mentioned anything in question then you should know that it is in radian form.
Recently Updated Pages
Geometry of Complex Numbers – Topics, Reception, Audience and Related Readings

JEE Main 2021 July 25 Shift 1 Question Paper with Answer Key

JEE Main 2021 July 22 Shift 2 Question Paper with Answer Key

JEE Electricity and Magnetism Important Concepts and Tips for Exam Preparation

JEE Energetics Important Concepts and Tips for Exam Preparation

JEE Isolation, Preparation and Properties of Non-metals Important Concepts and Tips for Exam Preparation

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility, & More

JEE Main 2025: Derivation of Equation of Trajectory in Physics

Electric Field Due to Uniformly Charged Ring for JEE Main 2025 - Formula and Derivation

Displacement-Time Graph and Velocity-Time Graph for JEE

Degree of Dissociation and Its Formula With Solved Example for JEE

Free Radical Substitution Mechanism of Alkanes for JEE Main 2025

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

JEE Advanced 2025: Dates, Registration, Syllabus, Eligibility Criteria and More

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry

JEE Advanced 2025 Notes

Learn About Angle Of Deviation In Prism: JEE Main Physics 2025

List of Fastest Century in IPL History
