
If \[x\] is measured in degrees, then \[\dfrac{d}{{dx}}(\cos x)\] is equal to
A. \[ - \sin x\]
B. \[ - (\dfrac{{180}}{\pi })\sin x\]
C. \[ - (\dfrac{\pi }{{180}})\sin x\]
D. \[\sin x\]
Answer
217.8k+ views
Hint: First we have to convert degree to radian. Derivative of a trigonometric function in degree does not exist. Then we will apply the formula \[\dfrac{d}{{dx}}\left( {\cos x} \right) = - \sin x\]
Formula Used: To the covert degree to radian, we have the formula \[{180^ \circ } = {\pi ^c}\]. \[\dfrac{d}{{dx}}(\cos x) = - \sin x\], where x is measured in radian. We can write \[\dfrac{{dy}}{{dx}} = \dfrac{{dy}}{{dz}}.\dfrac{{dz}}{{dx}}\] where y is a function of z and z is a function of x. This is called Chain Rule. Using this rule, we have \[\dfrac{d}{{dx}}(\cos y) = \dfrac{d}{{dy}}(\cos y)\dfrac{{dy}}{{dx}}\]
Complete step-by-step solution:
Here, x is measured in degrees. First, we have to convert the degree to radian. Derivative of trigonometric function in degree does not exist. Only the derivative of the trigonometric function in radian exists.
Therefore, \[{180^ \circ } = {\pi ^c}\]
or, \[{1^ \circ } = \dfrac{{{\pi ^c}}}{{180}}\]
or, \[{x^ \circ } = \dfrac{\pi }{{180}}{x^c}\]
Therefore,
\[\dfrac{d}{{dx}}(\cos {x^ \circ }) = \dfrac{d}{{dx}}(\cos \dfrac{{\pi {x^c}}}{{180}})\]
Let \[y = \dfrac{{\pi x}}{{180}}\]
\[\dfrac{d}{{dx}}(\cos y) = \dfrac{d}{{dy}}(\cos y)\dfrac{{dy}}{{dx}}\] [Using Chain Rule]
\[ = ( - \sin y)\dfrac{d}{{dx}}(\dfrac{{\pi x}}{{180}})\]
\[ = - \sin y \times \dfrac{\pi }{{180}} \times \dfrac{d}{{dx}}(x)\]
\[ = - \sin y \times \dfrac{\pi }{{180}} \times 1\]
\[ = \dfrac{\pi }{{180}} \times - \sin y\]
\[ = - \dfrac{\pi }{{180}}\sin (\dfrac{{\pi x}}{{180}})\]
Hence, option C. is correct.
Note: Students often mistake not to convert degree to radian. They only take derivatives and find the relevant option to choose the correct answer. They do not check whether it is in degree form or radian form. So, after getting the question, you have to notice carefully the question that is given in either degree form or radian form. If it is in radian form then you don’t convert. But if it is in degree form then you must convert it to radian form using the above formula and then take the derivative using the Chain Rule. If there is not mentioned anything in question then you should know that it is in radian form.
Formula Used: To the covert degree to radian, we have the formula \[{180^ \circ } = {\pi ^c}\]. \[\dfrac{d}{{dx}}(\cos x) = - \sin x\], where x is measured in radian. We can write \[\dfrac{{dy}}{{dx}} = \dfrac{{dy}}{{dz}}.\dfrac{{dz}}{{dx}}\] where y is a function of z and z is a function of x. This is called Chain Rule. Using this rule, we have \[\dfrac{d}{{dx}}(\cos y) = \dfrac{d}{{dy}}(\cos y)\dfrac{{dy}}{{dx}}\]
Complete step-by-step solution:
Here, x is measured in degrees. First, we have to convert the degree to radian. Derivative of trigonometric function in degree does not exist. Only the derivative of the trigonometric function in radian exists.
Therefore, \[{180^ \circ } = {\pi ^c}\]
or, \[{1^ \circ } = \dfrac{{{\pi ^c}}}{{180}}\]
or, \[{x^ \circ } = \dfrac{\pi }{{180}}{x^c}\]
Therefore,
\[\dfrac{d}{{dx}}(\cos {x^ \circ }) = \dfrac{d}{{dx}}(\cos \dfrac{{\pi {x^c}}}{{180}})\]
Let \[y = \dfrac{{\pi x}}{{180}}\]
\[\dfrac{d}{{dx}}(\cos y) = \dfrac{d}{{dy}}(\cos y)\dfrac{{dy}}{{dx}}\] [Using Chain Rule]
\[ = ( - \sin y)\dfrac{d}{{dx}}(\dfrac{{\pi x}}{{180}})\]
\[ = - \sin y \times \dfrac{\pi }{{180}} \times \dfrac{d}{{dx}}(x)\]
\[ = - \sin y \times \dfrac{\pi }{{180}} \times 1\]
\[ = \dfrac{\pi }{{180}} \times - \sin y\]
\[ = - \dfrac{\pi }{{180}}\sin (\dfrac{{\pi x}}{{180}})\]
Hence, option C. is correct.
Note: Students often mistake not to convert degree to radian. They only take derivatives and find the relevant option to choose the correct answer. They do not check whether it is in degree form or radian form. So, after getting the question, you have to notice carefully the question that is given in either degree form or radian form. If it is in radian form then you don’t convert. But if it is in degree form then you must convert it to radian form using the above formula and then take the derivative using the Chain Rule. If there is not mentioned anything in question then you should know that it is in radian form.
Recently Updated Pages
Arithmetic, Geometric & Harmonic Progressions Explained

Cartesian Form of Vector Explained: Formula, Examples & Uses

Apparent Frequency Explained: Formula, Uses & Examples

Calorimetry: Definition, Principles & Calculations

Centrifugal Force Explained: Definition, Formula & Examples

Charge in a Magnetic Field: Definition, Formula & Examples

Trending doubts
JEE Main 2026: Application Form Open, Exam Dates, Syllabus, Eligibility & Question Papers

Derivation of Equation of Trajectory Explained for Students

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Angle of Deviation in a Prism

Understanding Collisions: Types and Examples for Students

Understanding Atomic Structure for Beginners

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

How to Convert a Galvanometer into an Ammeter or Voltmeter

Ideal and Non-Ideal Solutions Explained for Class 12 Chemistry

Degree of Dissociation: Meaning, Formula, Calculation & Uses

Understanding Electromagnetic Waves and Their Importance

Understanding Average and RMS Value in Electrical Circuits

