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If the object lies beyond the center of curvature C, then the image formed between C and F in front of a concave mirror is:
A) Real and inverted
B) Virtual and inverted
C) Large in size
D) None of these

Last updated date: 19th Apr 2024
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MVSAT 2024
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Hint: Rays emerging from a point meet at another point after reflection, and that point is called the image of the first point. The image is real if the rays converge to the point and it is virtual if the rays do not meet it but appear to diverge from a point when the rays are produced backward. During image formation we assume that the rays are paraxial, i.e., they are incident at points close to the pole P of the mirror and make small angles with the principal axis.

Complete solution:

Now consider the following ray diagram. The object AB lies beyond the center of curvature. We consider two different rays emerging from the object. One parallel to the principal axis and the other directed towards the center of curvature of the mirror. The line parallel to the principal axis, after reflection at point D, will go through the focus F. A ray BE passing through the center of curvature will reflect in the same direction and path.
Now you can see clearly that the rays are converging to the point A’. Therefore the formed image will be A’B’. The image formed is real and inverted.

Hence, the correct option is A.

Note: When the object is kept at infinity the point-size image is formed at the focus of the concave mirror. When the object is kept at the center of curvature the formed image will be inverted and the same size. When the object lies between C and F the formed image will be always beyond the center of curvature.