
If the ionic product of water is \[1.96 \times {10^{ - 14}}\]at \[35^\circ C\]. What is its value at \[10^\circ C\]?
(A) \[2.95 \times {10^{ - 14}}\]
(B) \[1.96 \times {10^{ - 7}}\]
(C) \[2.95 \times {10^{ - 15}}\]
(D) \[3.9 \times {10^{ - 12}}\]
Answer
221.1k+ views
Hint: The concentration of the ions in water at a specific temperature is known as the ionic product of water. When formulating the expression for ionic products, the water molecule itself is not taken into account.
Complete Step by Step Solution:
In the question, at \[{35^0}C\] the value of ionic product of water \[ = 1.96 \times {10^{ - 14}}\] is given.
Water can self-ionize, but only to a small degree. The hydronium ion, which has a positive charge, and the hydroxide ion, which has a negative charge, are the end products of the collision between the two water molecules.
\[{H_2}O(l) + {H_2}O(l) \rightleftharpoons {H_3}{O^ + }(aq) + O{H^ - }(aq)\]
Which is often simplified as \[{H_2}O(l) + \rightleftharpoons {H^ + }(aq) + O{H^ - }(aq)\]
The ionic product of water is the term for the equilibrium constant for the expression for self-ionisation of water. \[{K_W}\] is used as the symbol for ionic products of water.
\[{K_W} = \left[ {{H^ + }} \right]\left[ {O{H^ - }} \right]\]
The ionic product of water is the product of concentration of \[O{H^ - }\]and \[{H^ + }\]ions.
The temperature and the ionic product have a direct relationship; that is, the ionic product is directly proportional to temperature. The ionic product also diminishes as the temperature drops.
According to the given information, the temperature is decreasing \[\left( {{{10}^0}C} \right)\]. So, the ionic product of water also decreases.
From the given options it can be observed that \[2.95 \times {10^{ - 15}}\] is the only value less than the present value.
Therefore, the correct option is: (C) \[2.95 \times {10^{ - 15}}\].
Note: It should be noted that each aqueous solution whether it is acidic, basic or neutral possesses both hydrogen \[{H^ + }\]ion and hydroxyl \[O{H^ - }\] ion that is present in the same or different proportions. But the ionic product concentration \[{K_W}\] of the water always remains constant.
Complete Step by Step Solution:
In the question, at \[{35^0}C\] the value of ionic product of water \[ = 1.96 \times {10^{ - 14}}\] is given.
Water can self-ionize, but only to a small degree. The hydronium ion, which has a positive charge, and the hydroxide ion, which has a negative charge, are the end products of the collision between the two water molecules.
\[{H_2}O(l) + {H_2}O(l) \rightleftharpoons {H_3}{O^ + }(aq) + O{H^ - }(aq)\]
Which is often simplified as \[{H_2}O(l) + \rightleftharpoons {H^ + }(aq) + O{H^ - }(aq)\]
The ionic product of water is the term for the equilibrium constant for the expression for self-ionisation of water. \[{K_W}\] is used as the symbol for ionic products of water.
\[{K_W} = \left[ {{H^ + }} \right]\left[ {O{H^ - }} \right]\]
The ionic product of water is the product of concentration of \[O{H^ - }\]and \[{H^ + }\]ions.
The temperature and the ionic product have a direct relationship; that is, the ionic product is directly proportional to temperature. The ionic product also diminishes as the temperature drops.
According to the given information, the temperature is decreasing \[\left( {{{10}^0}C} \right)\]. So, the ionic product of water also decreases.
From the given options it can be observed that \[2.95 \times {10^{ - 15}}\] is the only value less than the present value.
Therefore, the correct option is: (C) \[2.95 \times {10^{ - 15}}\].
Note: It should be noted that each aqueous solution whether it is acidic, basic or neutral possesses both hydrogen \[{H^ + }\]ion and hydroxyl \[O{H^ - }\] ion that is present in the same or different proportions. But the ionic product concentration \[{K_W}\] of the water always remains constant.
Recently Updated Pages
The hybridization and shape of NH2 ion are a sp2 and class 11 chemistry JEE_Main

What is the pH of 001 M solution of HCl a 1 b 10 c class 11 chemistry JEE_Main

Aromatization of nhexane gives A Benzene B Toluene class 11 chemistry JEE_Main

Show how you will synthesise i 1Phenylethanol from class 11 chemistry JEE_Main

The enolic form of acetone contains a 10sigma bonds class 11 chemistry JEE_Main

Which of the following Compounds does not exhibit tautomerism class 11 chemistry JEE_Main

Trending doubts
JEE Main 2026: Application Form Open, Exam Dates, Syllabus, Eligibility & Question Papers

Derivation of Equation of Trajectory Explained for Students

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Angle of Deviation in a Prism

How to Convert a Galvanometer into an Ammeter or Voltmeter

Degree of Dissociation: Meaning, Formula, Calculation & Uses

Other Pages
NCERT Solutions For Class 11 Chemistry Chapter 7 Redox Reaction

JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Hydrocarbons Class 11 Chemistry Chapter 9 CBSE Notes - 2025-26

Thermodynamics Class 11 Chemistry Chapter 5 CBSE Notes - 2025-26

NCERT Solutions ForClass 11 Chemistry Chapter Chapter 5 Thermodynamics

Equilibrium Class 11 Chemistry Chapter 6 CBSE Notes - 2025-26

