
If the direction ratios of a line are proportional to $1, - 3,2,$ then its direction cosines are:
A. $\dfrac{1}{{\sqrt {14} }},\dfrac{{ - 3}}{{\sqrt {14} }},\dfrac{2}{{\sqrt {14} }}$
B. $\dfrac{1}{{\sqrt {14} }},\dfrac{2}{{\sqrt {14} }},\dfrac{3}{{\sqrt {14} }}$
C. $\dfrac{{ - 1}}{{\sqrt {14} }},\dfrac{3}{{\sqrt {14} }},\dfrac{{ - 2}}{{\sqrt {14} }}$
D. $\dfrac{{ - 1}}{{\sqrt {14} }},\dfrac{{ - 2}}{{\sqrt {14} }},\dfrac{{ - 3}}{{\sqrt {14} }}$
Answer
232.8k+ views
Hint: In this question as direction ratio is given so to determine direction cosines, we use the correlation between direction ratios and direction cosines. Therefore, we use the formula of direction cosine where we can place the given value of the ratio.
Formula Used:
Directional cosines of a line segment which has direction ratio $a, b, c$ is:
\[ \pm \left( {\dfrac{a}{{\sqrt {{a^2} + {b^2} + {c^2}} }},\dfrac{b}{{\sqrt {{a^2} + {b^2} + {c^2}} }},\dfrac{c}{{\sqrt {{a^2} + {b^2} + {c^2}} }}} \right)\]
Complete Step-by-step solution
It is given that the direction ratio of the line segment is proportional to $1, - 3,2$.
So, the direction cosine of the line will be given by using above mentioned formula, where $a = 1,b = - 3,c = 2$
Now, on putting the values of $a,b,c$ in the formula mentioned above, we get:
Directional cosines \[ = \pm \left( {\dfrac{1}{{\sqrt {{1^2} + {{( - 3)}^2} + {2^2}} }},\dfrac{{ - 3}}{{\sqrt {{1^2} + {{( - 3)}^2} + {2^2}} }},\dfrac{2}{{\sqrt {{1^2} + {{( - 3)}^2} + {2^2}} }}} \right)\]
\[ = \pm \left( {\dfrac{1}{{\sqrt {1 + 9 + 4} }},\dfrac{{ - 3}}{{\sqrt {1 + 9 + 4} }},\dfrac{2}{{\sqrt {1 + 9 + 4} }}} \right)\]
\[ = \pm \left( {\dfrac{1}{{\sqrt {14} }},\dfrac{{ - 3}}{{\sqrt {14} }},\dfrac{2}{{\sqrt {14} }}} \right)\]
So, we can say that the direction cosine can be \[ + \left( {\dfrac{1}{{\sqrt {14} }},\dfrac{{ - 3}}{{\sqrt {14} }},\dfrac{2}{{\sqrt {14} }}} \right)\]or\[\left( {\dfrac{{ - 1}}{{\sqrt {14} }},\dfrac{3}{{\sqrt {14} }},\dfrac{{ - 2}}{{\sqrt {14} }}} \right)\]
It can be written as \[ + \left( {\dfrac{1}{{\sqrt {14} }},\dfrac{{ - 3}}{{\sqrt {14} }},\dfrac{2}{{\sqrt {14} }}} \right)\] and \[\left( {\dfrac{{ - 1}}{{\sqrt {14} }},\dfrac{3}{{\sqrt {14} }},\dfrac{{ - 2}}{{\sqrt {14} }}} \right)\]
Hence the correct option can be either A and C.
Note: It is not necessary that a question can only have one answer. Like the given question has multiple answers because sometimes a value can be both positive and negative and to decide between them without any other information given is not possible. This question comes under the concept of directional cosines and vectors.
Formula Used:
Directional cosines of a line segment which has direction ratio $a, b, c$ is:
\[ \pm \left( {\dfrac{a}{{\sqrt {{a^2} + {b^2} + {c^2}} }},\dfrac{b}{{\sqrt {{a^2} + {b^2} + {c^2}} }},\dfrac{c}{{\sqrt {{a^2} + {b^2} + {c^2}} }}} \right)\]
Complete Step-by-step solution
It is given that the direction ratio of the line segment is proportional to $1, - 3,2$.
So, the direction cosine of the line will be given by using above mentioned formula, where $a = 1,b = - 3,c = 2$
Now, on putting the values of $a,b,c$ in the formula mentioned above, we get:
Directional cosines \[ = \pm \left( {\dfrac{1}{{\sqrt {{1^2} + {{( - 3)}^2} + {2^2}} }},\dfrac{{ - 3}}{{\sqrt {{1^2} + {{( - 3)}^2} + {2^2}} }},\dfrac{2}{{\sqrt {{1^2} + {{( - 3)}^2} + {2^2}} }}} \right)\]
\[ = \pm \left( {\dfrac{1}{{\sqrt {1 + 9 + 4} }},\dfrac{{ - 3}}{{\sqrt {1 + 9 + 4} }},\dfrac{2}{{\sqrt {1 + 9 + 4} }}} \right)\]
\[ = \pm \left( {\dfrac{1}{{\sqrt {14} }},\dfrac{{ - 3}}{{\sqrt {14} }},\dfrac{2}{{\sqrt {14} }}} \right)\]
So, we can say that the direction cosine can be \[ + \left( {\dfrac{1}{{\sqrt {14} }},\dfrac{{ - 3}}{{\sqrt {14} }},\dfrac{2}{{\sqrt {14} }}} \right)\]or\[\left( {\dfrac{{ - 1}}{{\sqrt {14} }},\dfrac{3}{{\sqrt {14} }},\dfrac{{ - 2}}{{\sqrt {14} }}} \right)\]
It can be written as \[ + \left( {\dfrac{1}{{\sqrt {14} }},\dfrac{{ - 3}}{{\sqrt {14} }},\dfrac{2}{{\sqrt {14} }}} \right)\] and \[\left( {\dfrac{{ - 1}}{{\sqrt {14} }},\dfrac{3}{{\sqrt {14} }},\dfrac{{ - 2}}{{\sqrt {14} }}} \right)\]
Hence the correct option can be either A and C.
Note: It is not necessary that a question can only have one answer. Like the given question has multiple answers because sometimes a value can be both positive and negative and to decide between them without any other information given is not possible. This question comes under the concept of directional cosines and vectors.
Recently Updated Pages
Geometry of Complex Numbers Explained

JEE General Topics in Chemistry Important Concepts and Tips

JEE Extractive Metallurgy Important Concepts and Tips for Exam Preparation

JEE Amino Acids and Peptides Important Concepts and Tips for Exam Preparation

JEE Atomic Structure and Chemical Bonding important Concepts and Tips

Electricity and Magnetism Explained: Key Concepts & Applications

Trending doubts
JEE Main 2026: Session 2 Registration Open, City Intimation Slip, Exam Dates, Syllabus & Eligibility

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

JEE Main Marking Scheme 2026- Paper-Wise Marks Distribution and Negative Marking Details

Understanding the Angle of Deviation in a Prism

Hybridisation in Chemistry – Concept, Types & Applications

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Understanding the Electric Field of a Uniformly Charged Ring

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry

Derivation of Equation of Trajectory Explained for Students

Understanding Electromagnetic Waves and Their Importance

Understanding How a Current Loop Acts as a Magnetic Dipole

