Question

If $f(x) = 3{x^2} + 15x + 5$, then the approximate value of $f(3.02)$is
A.47.66
B.57.66
C.67.66
D.77.66

Answer 1

Hint: Here the value of $f(3.02)$ is calculated by substituting the value of $x$ as 3.02 in given f(x).

Complete step-by-step answer:

The Given function is $f(x) = 3{x^2} + 15x + 5$
Now putting the value of $x$ as 3.02 we get
$
  f(3.02) = 3{(3.02)^2} + 15(3.02) + 5 \\
  f(3.02) = 3(9.1204) + 45.3 + 5 \\
  f(3.02) = 27.3612 + 45.3 + 5 \\
  f(3.02) = 77.6612 \simeq 77.66 \\
$
So the required solution is (d) 77.66.

Note: In these types of questions, we get a solution just by substituting the value of $x$ in the given function. One should take care of decimal points while keeping the calculation to appropriate value.