Answer
Verified
39.9k+ views
Hint: To solve this, proceed step wise and identify A, B and then arrive at C. Remember that tin with hydrochloric acid will reduce nitrobenzene and will give you an amine. Upon reaction with sodium nitride the amine will give you a salt. The salt will react with sodium amide and again arrive at phenyl amine.
Complete step by step solution:
To solve this, let’s see the reaction of nitrobenzene with the given reagents and then arrive at the final result.
In the first step, nitrobenzene reacts with tin and hydrochloric acid. It is a redox reaction and here the nitrobenzene is reduced to phenylamine. The reaction proceeds via formation of a phenyl ammonium cation by reduction of nitrobenzene. We can write the reaction as-
So, phenylamine is ‘A’. To this, sodium nitrite is added which will cause the amine to undergo diazotization. The hydrochloric acid in the reaction will react with it thus leading to the formation of a diazonium salt of benzene called benzene diazonium chloride. We can write the reaction as-
The diazonium salt thus obtained is our ‘B’.
To this diazonium salt when we add sodium amide we will again get the phenyl amine. We can write the reaction as-
The phenyl amine is ‘C’. It is also known as aniline.
We can see from the above discussion that the ‘C’ in the reaction series is aniline.
Therefore, the correct answer is option [D] Aniline.
Note: Primary amines give us a diazonium salt which forms alcohols in addition to water but secondary amines have one hydrogen atom attached to them therefore, they cannot complete the diazotization reaction and give us a yellow oily nitrosamine product. Three degree amines have no hydrogen atoms attached to them thus they undergo simple acid- base reactions and give us soluble salts.
Complete step by step solution:
To solve this, let’s see the reaction of nitrobenzene with the given reagents and then arrive at the final result.
In the first step, nitrobenzene reacts with tin and hydrochloric acid. It is a redox reaction and here the nitrobenzene is reduced to phenylamine. The reaction proceeds via formation of a phenyl ammonium cation by reduction of nitrobenzene. We can write the reaction as-
So, phenylamine is ‘A’. To this, sodium nitrite is added which will cause the amine to undergo diazotization. The hydrochloric acid in the reaction will react with it thus leading to the formation of a diazonium salt of benzene called benzene diazonium chloride. We can write the reaction as-
The diazonium salt thus obtained is our ‘B’.
To this diazonium salt when we add sodium amide we will again get the phenyl amine. We can write the reaction as-
The phenyl amine is ‘C’. It is also known as aniline.
We can see from the above discussion that the ‘C’ in the reaction series is aniline.
Therefore, the correct answer is option [D] Aniline.
Note: Primary amines give us a diazonium salt which forms alcohols in addition to water but secondary amines have one hydrogen atom attached to them therefore, they cannot complete the diazotization reaction and give us a yellow oily nitrosamine product. Three degree amines have no hydrogen atoms attached to them thus they undergo simple acid- base reactions and give us soluble salts.
Recently Updated Pages
silver wire has diameter 04mm and resistivity 16 times class 12 physics JEE_Main
A parallel plate capacitor has a capacitance C When class 12 physics JEE_Main
Let gx 1 + x x and fx left beginarray20c 1x 0 0x 0 class 12 maths JEE_Main
A series combination of n1 capacitors each of value class 12 physics JEE_Main
When propyne is treated with aqueous H2SO4 in presence class 12 chemistry JEE_Main
Which of the following is not true in the case of motion class 12 physics JEE_Main
Other Pages
The mole fraction of the solute in a 1 molal aqueous class 11 chemistry JEE_Main
Explain the construction and working of a GeigerMuller class 12 physics JEE_Main
Dissolving 120g of urea molwt60 in 1000g of water gave class 11 chemistry JEE_Main
Formula for number of images formed by two plane mirrors class 12 physics JEE_Main
A closed organ pipe and an open organ pipe are tuned class 11 physics JEE_Main
when an object Is placed at a distance of 60 cm from class 12 physics JEE_Main