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# Identify A and B in the following reactions:${\text{Ba}}{{\text{C}}_{\text{2}}}{\text{ + }}{{\text{N}}_{\text{2}}}\xrightarrow{{\text{\Delta }}}{\text{B}}$${\text{Ca}}{{\text{C}}_{\text{2}}}{\text{ + }}{{\text{N}}_{\text{2}}}\xrightarrow{{\text{\Delta }}}{\text{A}}$A.${\text{A: Ca(N = C = N) ; B: Ba(C}} \equiv {\text{N)}}$B.${\text{A: Ca(N - C - N) ; B: B}}{{\text{a}}_{\text{2}}}{{\text{(C}} \equiv {\text{N)}}_{\text{4}}}$C.${\text{A: Ca(N = C = N}}{{\text{)}}_{\text{2}}}{\text{ ; B: Ba(C}} \equiv {\text{N}}{{\text{)}}_{\text{2}}}$D.${\text{A: Ca(N - C - N}}{{\text{)}}_{\text{2}}}{\text{ ; B: B}}{{\text{a}}_{\text{2}}}{{\text{(C}} \equiv {\text{N)}}_{\text{4}}}$

Last updated date: 20th Jun 2024
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Hint: Carbides are prepared at high temperatures in electric arc furnaces. They are mostly formed from oxides reacting with carbon. While nitrogen is an inert gas, in high temperatures it reacts with carbides to form cyanides and cyanamide. The compound formed depends upon the valency of the other element.

Calcium carbide is formed from the reaction of lime with coke in an electric arc furnace. It is a colourless crystalline solid. Calcium carbide when heated at about ${\text{110}}{{\text{0}}^{\text{o}}}{\text{C}}$ with nitrogen gas for about several hours. Calcium cyanamide is produced. It is then cooled to ambient temperature and purified by leaching. The reaction goes as follows:
${\text{Ca}}{{\text{C}}_{\text{2}}}{\text{ + }}{{\text{N}}_{\text{2}}}\xrightarrow{{\text{Delta }}}{\text{CaC}}{{\text{N}}_{\text{2}}}$
The product formed is present as: ${\text{Ca(N = C = N)}}$ .
${\text{Ba}}{{\text{C}}_{\text{2}}}{\text{ + }}{{\text{N}}_{\text{2}}}\xrightarrow{{\text{Delta }}}{\text{Ba(CN}}{{\text{)}}_{\text{2}}}$
The product is present in the form of ${\text{Ba(C}} \equiv {\text{N}}{{\text{)}}_{\text{2}}}$ .
$\therefore$ The correct option is Option C, i.e. ${\text{A: Ca(N = C = N}}{{\text{)}}_{\text{2}}}{\text{ ; B: Ba(C}} \equiv {\text{N}}{{\text{)}}_{\text{2}}}$ .