Answer
Verified
40.8k+ views
Hint: In this question consider the gravitational force on the surface of the moon be ${g_m}$ that is ${g_m} = \dfrac{g}{6} = \dfrac{{9.8}}{6}$. Then use that the force acting upon the body is actually the weight of the body and is the product of the mass and acceleration due to gravity that is $F = W = Mg$. This will help approaching the problem.
Complete step-by-step solution -
According to Newton’s second law of motion the force acting on the body is the product of the mass of the body and the acceleration by which the body is moving.
In case if a body is at a rest position the force acting on the body is equal to the weight of the body which is acting downward on the body and this is equal to the product of mass of the body and the acceleration due to gravity.
$ \Rightarrow F = W = Mg$Newton (N)..................... (1)
Where, W = weight of the body, M = mass of the body and g = acceleration due to gravity.
Now it is given that the mass (M) of an object = 10Kg.
And gravitational force on the surface of the moon is (1/6) times the gravitational force on the earth.
As we know on the earth surface the gravitational force, g = 9.8 m/s2.
So on the surface of the moon the gravitational force will be, ${g_m} = \dfrac{g}{6} = \dfrac{{9.8}}{6}$ m/s2.
Now from equation (1) weight of the object on the surface of the earth is,
$ \Rightarrow {W_e} = 10 \times 9.8 = 98N$
And the weight of the object on the surface of the moon is,
$ \Rightarrow {W_m} = 10 \times \dfrac{{9.8}}{6} = 16.66N$
So this is the required weight of the object on the surface of the earth and on the moon respectively.
Note – The main reason behind the lesser gravity on the surface of the moon as compared to the earth is that moon’s size is comparatively very less as compared to the earth moreover moon is also less dense as compared to that of earth. Less dense allows weak force of gravitational attraction on the moon.
Complete step-by-step solution -
According to Newton’s second law of motion the force acting on the body is the product of the mass of the body and the acceleration by which the body is moving.
In case if a body is at a rest position the force acting on the body is equal to the weight of the body which is acting downward on the body and this is equal to the product of mass of the body and the acceleration due to gravity.
$ \Rightarrow F = W = Mg$Newton (N)..................... (1)
Where, W = weight of the body, M = mass of the body and g = acceleration due to gravity.
Now it is given that the mass (M) of an object = 10Kg.
And gravitational force on the surface of the moon is (1/6) times the gravitational force on the earth.
As we know on the earth surface the gravitational force, g = 9.8 m/s2.
So on the surface of the moon the gravitational force will be, ${g_m} = \dfrac{g}{6} = \dfrac{{9.8}}{6}$ m/s2.
Now from equation (1) weight of the object on the surface of the earth is,
$ \Rightarrow {W_e} = 10 \times 9.8 = 98N$
And the weight of the object on the surface of the moon is,
$ \Rightarrow {W_m} = 10 \times \dfrac{{9.8}}{6} = 16.66N$
So this is the required weight of the object on the surface of the earth and on the moon respectively.
Note – The main reason behind the lesser gravity on the surface of the moon as compared to the earth is that moon’s size is comparatively very less as compared to the earth moreover moon is also less dense as compared to that of earth. Less dense allows weak force of gravitational attraction on the moon.
Recently Updated Pages
silver wire has diameter 04mm and resistivity 16 times class 12 physics JEE_Main
A parallel plate capacitor has a capacitance C When class 12 physics JEE_Main
A series combination of n1 capacitors each of value class 12 physics JEE_Main
When propyne is treated with aqueous H2SO4 in presence class 12 chemistry JEE_Main
Which of the following is not true in the case of motion class 12 physics JEE_Main
The length of a potentiometer wire is 10m The distance class 12 physics JEE_MAIN
Other Pages
The radius of the sphere is 43 pm 01cm The percentage class 11 physics JEE_Main
The figure below shows regular hexagons with charges class 12 physics JEE_Main
Which halogen in its reference state will have the class 11 chemistry JEE_Main
when an object Is placed at a distance of 60 cm from class 12 physics JEE_Main
Two charges 9e and 3e are placed at a separation r class 12 physics JEE_Main
How many grams of concentrated nitric acid solution class 11 chemistry JEE_Main