
Gravitational force on the surface of the moon is only $\dfrac{1}{6}$ as strong as gravitational force on the earth. What is the weight in Newton of a 10Kg object on the moon and on the earth?
Answer
232.8k+ views
Hint: In this question consider the gravitational force on the surface of the moon be ${g_m}$ that is ${g_m} = \dfrac{g}{6} = \dfrac{{9.8}}{6}$. Then use that the force acting upon the body is actually the weight of the body and is the product of the mass and acceleration due to gravity that is $F = W = Mg$. This will help approaching the problem.
Complete step-by-step solution -
According to Newton’s second law of motion the force acting on the body is the product of the mass of the body and the acceleration by which the body is moving.
In case if a body is at a rest position the force acting on the body is equal to the weight of the body which is acting downward on the body and this is equal to the product of mass of the body and the acceleration due to gravity.
$ \Rightarrow F = W = Mg$Newton (N)..................... (1)
Where, W = weight of the body, M = mass of the body and g = acceleration due to gravity.
Now it is given that the mass (M) of an object = 10Kg.
And gravitational force on the surface of the moon is (1/6) times the gravitational force on the earth.
As we know on the earth surface the gravitational force, g = 9.8 m/s2.
So on the surface of the moon the gravitational force will be, ${g_m} = \dfrac{g}{6} = \dfrac{{9.8}}{6}$ m/s2.
Now from equation (1) weight of the object on the surface of the earth is,
$ \Rightarrow {W_e} = 10 \times 9.8 = 98N$
And the weight of the object on the surface of the moon is,
$ \Rightarrow {W_m} = 10 \times \dfrac{{9.8}}{6} = 16.66N$
So this is the required weight of the object on the surface of the earth and on the moon respectively.
Note – The main reason behind the lesser gravity on the surface of the moon as compared to the earth is that moon’s size is comparatively very less as compared to the earth moreover moon is also less dense as compared to that of earth. Less dense allows weak force of gravitational attraction on the moon.
Complete step-by-step solution -
According to Newton’s second law of motion the force acting on the body is the product of the mass of the body and the acceleration by which the body is moving.
In case if a body is at a rest position the force acting on the body is equal to the weight of the body which is acting downward on the body and this is equal to the product of mass of the body and the acceleration due to gravity.
$ \Rightarrow F = W = Mg$Newton (N)..................... (1)
Where, W = weight of the body, M = mass of the body and g = acceleration due to gravity.
Now it is given that the mass (M) of an object = 10Kg.
And gravitational force on the surface of the moon is (1/6) times the gravitational force on the earth.
As we know on the earth surface the gravitational force, g = 9.8 m/s2.
So on the surface of the moon the gravitational force will be, ${g_m} = \dfrac{g}{6} = \dfrac{{9.8}}{6}$ m/s2.
Now from equation (1) weight of the object on the surface of the earth is,
$ \Rightarrow {W_e} = 10 \times 9.8 = 98N$
And the weight of the object on the surface of the moon is,
$ \Rightarrow {W_m} = 10 \times \dfrac{{9.8}}{6} = 16.66N$
So this is the required weight of the object on the surface of the earth and on the moon respectively.
Note – The main reason behind the lesser gravity on the surface of the moon as compared to the earth is that moon’s size is comparatively very less as compared to the earth moreover moon is also less dense as compared to that of earth. Less dense allows weak force of gravitational attraction on the moon.
Recently Updated Pages
Circuit Switching vs Packet Switching: Key Differences Explained

Dimensions of Pressure in Physics: Formula, Derivation & SI Unit

JEE General Topics in Chemistry Important Concepts and Tips

JEE Extractive Metallurgy Important Concepts and Tips for Exam Preparation

JEE Amino Acids and Peptides Important Concepts and Tips for Exam Preparation

JEE Atomic Structure and Chemical Bonding important Concepts and Tips

Trending doubts
JEE Main 2026: Session 2 Registration Open, City Intimation Slip, Exam Dates, Syllabus & Eligibility

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

JEE Main Marking Scheme 2026- Paper-Wise Marks Distribution and Negative Marking Details

Understanding the Angle of Deviation in a Prism

Hybridisation in Chemistry – Concept, Types & Applications

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Laws of Motion Class 11 Physics Chapter 4 CBSE Notes - 2025-26

Waves Class 11 Physics Chapter 14 CBSE Notes - 2025-26

Mechanical Properties of Fluids Class 11 Physics Chapter 9 CBSE Notes - 2025-26

Thermodynamics Class 11 Physics Chapter 11 CBSE Notes - 2025-26

Units And Measurements Class 11 Physics Chapter 1 CBSE Notes - 2025-26

