Answer
358.8k+ views
Hint: Electric flux is the rate of flow of the electric field through a given area. According to gauss law, the electric flux through a closed surface is equal to \[\dfrac{q}{{{\varepsilon _\circ }}}\], if q is the charge enclosed in it.
In case if a charge is placed at one of the corners of the cube then the amount of charge enclosed in it is eighth part of the charge so the flux is also the eighth part of \[\dfrac{q}{{{\varepsilon _\circ }}}\].
Formula used:
Gauss law: According to gauss law :- If a charge “q ” is enclosed in a closed surface then the net flux emerging out of the closed surface is \[\dfrac{q}{{{\varepsilon _\circ }}}\]. Gauss law is only applicable for closed bodies.
Complete step by step solution:
According to gauss law, the electric flux through a closed surface is equal to \[\dfrac{q}{{{\varepsilon _\circ }}}\], if q is the charge enclosed in it.
![](https://www.vedantu.com/question-sets/c2a9542b-1926-425b-9c1c-b56fe27f22035183155757954787312.png)
If the charge ‘q ’is placed at one of the corners of the cube, it will be divided into 8 such cubes. Therefore, electric flux through the one cube is the eighth part of \[\dfrac{q}{{{\varepsilon _\circ }}}\].
So electric flux (\[\varphi \]) is equal to \[\dfrac{q}{{8{\varepsilon _\circ }}}\].
Hence option (D) is the correct answer.
Gauss law is one of the four Maxwell’s equations which form the basis of classical electrodynamics.
Note: Electric flux has SI units of volt metres ( V m).
Electric flux is the rate of flow of electric field through a given area. Electric flux is proportional to the number of electric field lines going through a virtual surface. Gauss law can be used to derive the coulomb’s law and vice-versa.
In case if a charge is placed at one of the corners of the cube then the amount of charge enclosed in it is eighth part of the charge so the flux is also the eighth part of \[\dfrac{q}{{{\varepsilon _\circ }}}\].
Formula used:
Gauss law: According to gauss law :- If a charge “q ” is enclosed in a closed surface then the net flux emerging out of the closed surface is \[\dfrac{q}{{{\varepsilon _\circ }}}\]. Gauss law is only applicable for closed bodies.
Complete step by step solution:
According to gauss law, the electric flux through a closed surface is equal to \[\dfrac{q}{{{\varepsilon _\circ }}}\], if q is the charge enclosed in it.
![](https://www.vedantu.com/question-sets/c2a9542b-1926-425b-9c1c-b56fe27f22035183155757954787312.png)
If the charge ‘q ’is placed at one of the corners of the cube, it will be divided into 8 such cubes. Therefore, electric flux through the one cube is the eighth part of \[\dfrac{q}{{{\varepsilon _\circ }}}\].
So electric flux (\[\varphi \]) is equal to \[\dfrac{q}{{8{\varepsilon _\circ }}}\].
Hence option (D) is the correct answer.
Gauss law is one of the four Maxwell’s equations which form the basis of classical electrodynamics.
Note: Electric flux has SI units of volt metres ( V m).
Electric flux is the rate of flow of electric field through a given area. Electric flux is proportional to the number of electric field lines going through a virtual surface. Gauss law can be used to derive the coulomb’s law and vice-versa.
Recently Updated Pages
Write a composition in approximately 450 500 words class 10 english JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Arrange the sentences P Q R between S1 and S5 such class 10 english JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
What is the common property of the oxides CONO and class 10 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
What happens when dilute hydrochloric acid is added class 10 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
If four points A63B 35C4 2 and Dx3x are given in such class 10 maths JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
The area of square inscribed in a circle of diameter class 10 maths JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Other Pages
A boat takes 2 hours to go 8 km and come back to a class 11 physics JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Electric field due to uniformly charged sphere class 12 physics JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
In the ground state an element has 13 electrons in class 11 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
According to classical free electron theory A There class 11 physics JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Differentiate between homogeneous and heterogeneous class 12 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Excluding stoppages the speed of a bus is 54 kmph and class 11 maths JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)