
Find the upper quartile for the following distribution is given by the size of
Size of Items 1 2 3 4 5 6 7 Frequency 2 4 5 8 7 3 2
A. ${\left( {\dfrac{{31 + 1}}{4}} \right)^{th}}$ term
B. ${\left[ {2\left( {\dfrac{{31 + 1}}{4}} \right)} \right]^{th}}$ term
C. ${\left[ {3\left( {\dfrac{{31 + 1}}{4}} \right)} \right]^{th}}$ term
D. ${\left[ {4\left( {\dfrac{{31 + 1}}{4}} \right)} \right]^{th}}$ term
| Size of Items | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
| Frequency | 2 | 4 | 5 | 8 | 7 | 3 | 2 |
Answer
217.8k+ views
Hint: First, calculate the cumulative frequency of the given data set by adding the given frequencies. Then calculate the number of total observations. In the end, substitute the value of the total observations in the formula of the upper quartile to get the required answer.
Formula Used:
The formula of an upper quartile of a data set: ${Q_3} = {\left[ {3\left( {\dfrac{{n + 1}}{4}} \right)} \right]^{th}}$ term, where n is the number of observations
Complete step by step solution:
The given distribution of values is,
Let’s calculate the cumulative frequency of the above data.
From the above data table, we get
The total number of observations: $31$
Now apply the formula of an upper quartile ${Q_3} = {\left[ {3\left( {\dfrac{{n + 1}}{4}} \right)} \right]^{th}}$ term.
Substitute $n = 31$ in the above formula.
We get,
${Q_3} = {\left[ {3\left( {\dfrac{{31 + 1}}{4}} \right)} \right]^{th}}$ term
Option ‘C’ is correct
Additional Information:
The quartiles of a data set are the numbers used to divide a set of data into four equal parts, or quarters. The upper quartile is calculated by determining the median of the upper half of a data set.
Steps to find the upper quartile:
Step 1: Arrange the numbers of the data set in ascending order.
Step 2: Calculate how many numbers are in the data set.
Step 3: Use the formula ${Q_3} = \dfrac{3}{4}{\left( {n + 1} \right)^{th}}term$ to calculate the upper quartile.
Note: Students often get confused about the formulas of the first, second, and third quartiles.
Following are the formula of the quartiles:
First quartile: ${Q_1} = \dfrac{1}{4}{\left( {n + 1} \right)^{th}}term$
Second quartile: ${Q_2} = \dfrac{1}{2}{\left( {n + 1} \right)^{th}}term$
Third quartile: ${Q_3} = \dfrac{3}{4}{\left( {n + 1} \right)^{th}}term$
Formula Used:
The formula of an upper quartile of a data set: ${Q_3} = {\left[ {3\left( {\dfrac{{n + 1}}{4}} \right)} \right]^{th}}$ term, where n is the number of observations
Complete step by step solution:
The given distribution of values is,
| Size of Items | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
| Frequency | 2 | 4 | 5 | 8 | 7 | 3 | 2 |
Let’s calculate the cumulative frequency of the above data.
| Size of Items | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
| Frequency | 2 | 4 | 5 | 8 | 7 | 3 | 2 |
| Cumulative Frequency | 2 | 6 | 11 | 19 | 26 | 29 | 31 |
From the above data table, we get
The total number of observations: $31$
Now apply the formula of an upper quartile ${Q_3} = {\left[ {3\left( {\dfrac{{n + 1}}{4}} \right)} \right]^{th}}$ term.
Substitute $n = 31$ in the above formula.
We get,
${Q_3} = {\left[ {3\left( {\dfrac{{31 + 1}}{4}} \right)} \right]^{th}}$ term
Option ‘C’ is correct
Additional Information:
The quartiles of a data set are the numbers used to divide a set of data into four equal parts, or quarters. The upper quartile is calculated by determining the median of the upper half of a data set.
Steps to find the upper quartile:
Step 1: Arrange the numbers of the data set in ascending order.
Step 2: Calculate how many numbers are in the data set.
Step 3: Use the formula ${Q_3} = \dfrac{3}{4}{\left( {n + 1} \right)^{th}}term$ to calculate the upper quartile.
Note: Students often get confused about the formulas of the first, second, and third quartiles.
Following are the formula of the quartiles:
First quartile: ${Q_1} = \dfrac{1}{4}{\left( {n + 1} \right)^{th}}term$
Second quartile: ${Q_2} = \dfrac{1}{2}{\left( {n + 1} \right)^{th}}term$
Third quartile: ${Q_3} = \dfrac{3}{4}{\left( {n + 1} \right)^{th}}term$
Recently Updated Pages
Apparent Frequency Explained: Formula, Uses & Examples

Calorimetry: Definition, Principles & Calculations

Centrifugal Force Explained: Definition, Formula & Examples

Charge in a Magnetic Field: Definition, Formula & Examples

Combination of Capacitors: Series and Parallel Explained

Compressibility Factor Explained: Definition, Formula & Uses

Trending doubts
JEE Main 2026: Application Form Open, Exam Dates, Syllabus, Eligibility & Question Papers

Derivation of Equation of Trajectory Explained for Students

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Angle of Deviation in a Prism

Understanding Collisions: Types and Examples for Students

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Understanding Atomic Structure for Beginners

Ideal and Non-Ideal Solutions Explained for Class 12 Chemistry

Degree of Dissociation: Meaning, Formula, Calculation & Uses

Understanding Electromagnetic Waves and Their Importance

Understanding the Electric Field of a Uniformly Charged Ring

