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# Find the frequency of the wave that produces 3 crests and 2 troughs in 2 ms.A. 1250 HzB. 500 HzC. 800 HzD. 750 Hz

Last updated date: 13th Jun 2024
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Hint: The period of a wave refers to the time taken to complete one cycle. One cycle corresponds to one crest and one trough i.e., one wavelength. The frequency of the wave will be the reciprocal of the wave period.

Formula Used:
1. Period of a wave is given by, $T = \dfrac{t}{n}$ where $t$ is the time taken to complete $n$ number of cycles.
2. The frequency of a wave is given by, $f = \dfrac{1}{T}$ where $T$ is the period of the wave.

Step 1: Sketch a rough figure of the source wave and list its features.

The number of crests produced is 3 and the number of troughs produced is 2 in a time of 2 ms.
One crest and one trough can be considered to constitute one cycle. Here two crests and two troughs will then constitute two cycles and the remaining crest will constitute a half cycle. So a total of 2.5 cycles are produced in a given time of 2 ms.

Step 2: Calculate the period of the wave.
Period of the source wave is given by, $T = \dfrac{t}{n}$ --------- (1)
where $t$ is the time taken to complete $n$ number of cycles.
Substituting for $t = 2{\text{ms}}$ and $n = 2.5$ in equation (1) we get, $T = \dfrac{{0.002}}{{2.5}}800{\text{s}}$
So, the period of the wave is $T = 800{\text{s}}$ .

Step 3: Find the frequency of the wave using its period.
The frequency of a wave is given by, $f = \dfrac{1}{T}$ --------- (2) where $T$ is the period of the wave.
Substituting for $T = 800{\text{s}}$ in equation (2) we get, $f = \dfrac{1}{{800}} = 1250{\text{Hz}}$
$\therefore$ the frequency of the source wave is $f = 1250{\text{Hz}}$. So, the correct option is A.

Note: Frequency of a wave refers to the number of cycles completed in one second and so will be inversely proportional to the wave period. The unit of the wave period is seconds. So, while substituting the value for $t$ in equation (1) make sure that it is expressed in seconds as well. If not necessary conversion must be done. Here, $t = 2{\text{ms}}$ is converted to $t = 2 \times {10^{ - 3}}{\text{s}} = 0.002{\text{s}}$ and substituted in equation (1).