
Find the equation of a circle which passes through origin and cuts off intercepts $ - 2$ and $3$ from the axes.
Answer
219.6k+ views
Hint: Given, circle which passes through origin and cuts off intercepts $ - 2$ and $3$. We have to find the equation of the circle. First, we will put the given points in the general equation of the circle to find the unknown variable. After calculating those unknown we will put them in the general equation to get the required equation of the circle.
Formula Used: General equation of circle:
${x^2} + {y^2} + 2gx + 2fy + c = 0$
Complete step by step solution: A circle is a closed curve that extends outward from a set point known as the centre, with each point on the curve being equally spaced from the centre. ${\left( {x - h} \right)^2} + {\left( {y - k} \right)^2} = {r^2}$ is the equation for a circle having a centre (h, k) and $r$ radius.
This is the equation's standard form. Thus, we can quickly determine the equation of a circle if we know its radius and centre coordinates.
Given, circle which passes through origin and cuts off intercepts $ - 2$ and $3$.
We know the general equation of circle.
${x^2} + {y^2} + 2gx + 2fy + c = 0$ (1)
Clearly, given the circle passes through points
$C\left( {0,0} \right),\,P( - 2,0),\,Q(0,3)$
Putting the point C that is $x = 0$ and $y = 0$ in the equation (1)
$0 + 0 + 0 + 0 + c = 0$
$ \Rightarrow c = 0$
Putting the point P that is $x = - 2$ and $y = 0$ in the equation (1)
${( - 2)^2} + 0 + 2( - 2)g + 0 = 0$
$4 - 4g = 0$
Shifting 4 to other side.
$4g = 4$
Dividing both sides with 4
$g = 1$
Putting point Q that is $x = 0$ and $y = 3$ in the equation (1)
$0 + {(3)^2} + 0 + 2(3)f = 0$
$9 + 6f = 0$
Shifting 9 to other side
$6f = - 9$
Dividing both sides with 6
$f = - \dfrac{3}{2}$
Putting value of g, f and c in the equation (1)
${x^2} + {y^2} + 2(1)x + 2\left( {\dfrac{{ - 3}}{2}} \right)y + 0 = 0$
${x^2} + {y^2} + 2x - 3x = 0$
Hence, ${x^2} + {y^2} + 2x - 3x = 0$ is the required equation of the circle.
Note: Students should solve questions carefully to avoid any calculation error or any conceptual error. They should pay attention to the information which is given in the question. Ans should use the general equation of the circle that is ${x^2} + {y^2} + 2gx + 2fy + c = 0$ to get the correct answer without any difficulty.
Formula Used: General equation of circle:
${x^2} + {y^2} + 2gx + 2fy + c = 0$
Complete step by step solution: A circle is a closed curve that extends outward from a set point known as the centre, with each point on the curve being equally spaced from the centre. ${\left( {x - h} \right)^2} + {\left( {y - k} \right)^2} = {r^2}$ is the equation for a circle having a centre (h, k) and $r$ radius.
This is the equation's standard form. Thus, we can quickly determine the equation of a circle if we know its radius and centre coordinates.
Given, circle which passes through origin and cuts off intercepts $ - 2$ and $3$.
We know the general equation of circle.
${x^2} + {y^2} + 2gx + 2fy + c = 0$ (1)
Clearly, given the circle passes through points
$C\left( {0,0} \right),\,P( - 2,0),\,Q(0,3)$
Putting the point C that is $x = 0$ and $y = 0$ in the equation (1)
$0 + 0 + 0 + 0 + c = 0$
$ \Rightarrow c = 0$
Putting the point P that is $x = - 2$ and $y = 0$ in the equation (1)
${( - 2)^2} + 0 + 2( - 2)g + 0 = 0$
$4 - 4g = 0$
Shifting 4 to other side.
$4g = 4$
Dividing both sides with 4
$g = 1$
Putting point Q that is $x = 0$ and $y = 3$ in the equation (1)
$0 + {(3)^2} + 0 + 2(3)f = 0$
$9 + 6f = 0$
Shifting 9 to other side
$6f = - 9$
Dividing both sides with 6
$f = - \dfrac{3}{2}$
Putting value of g, f and c in the equation (1)
${x^2} + {y^2} + 2(1)x + 2\left( {\dfrac{{ - 3}}{2}} \right)y + 0 = 0$
${x^2} + {y^2} + 2x - 3x = 0$
Hence, ${x^2} + {y^2} + 2x - 3x = 0$ is the required equation of the circle.
Note: Students should solve questions carefully to avoid any calculation error or any conceptual error. They should pay attention to the information which is given in the question. Ans should use the general equation of the circle that is ${x^2} + {y^2} + 2gx + 2fy + c = 0$ to get the correct answer without any difficulty.
Recently Updated Pages
Chemical Equation - Important Concepts and Tips for JEE

JEE Main 2022 (July 29th Shift 1) Chemistry Question Paper with Answer Key

Conduction Explained: Definition, Examples & Science for Students

Analytical Method of Vector Addition Explained Simply

Atomic Size - Important Concepts and Tips for JEE

JEE Main 2022 (June 29th Shift 1) Maths Question Paper with Answer Key

Trending doubts
JEE Main 2026: Application Form Open, Exam Dates, Syllabus, Eligibility & Question Papers

Derivation of Equation of Trajectory Explained for Students

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Angle of Deviation in a Prism

Understanding Collisions: Types and Examples for Students

Understanding Atomic Structure for Beginners

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

How to Convert a Galvanometer into an Ammeter or Voltmeter

Understanding Centrifugal Force in Physics

JEE Main Marking Scheme 2026- Paper-Wise Marks Distribution and Negative Marking Details

Degree of Dissociation: Meaning, Formula, Calculation & Uses

Understanding Electromagnetic Waves and Their Importance

