Equipotential at a great distance from a collection of charges whose total sum is not zero are approximately:
(A) Spheres
(B) Planes
(C) Paraboloids
(D) Ellipsoids
Answer
267.6k+ views
Hint if we draw a surface in such a way that the electric potential is the same at all the points of the surface, it is called equipotential surface. The component of the electric field parallel to as the potential does not change in this direction. Thus, the electric field is perpendicular to the equipotential surface. For a point charge, the electric field is radial and the electric field is radial and the equipotential surface are concentric spheres with centers at the charge.
Complete Step by step solution
In this problem, the collection of charges, whose total sum is not zero, with regard to great distance can be considered as a point charge.
Now we know that the electric potential due to point charges $q$ is given by
$V = {k_e}\dfrac{q}{r}$
Since, ${k_e}$ and $q$ are constant
Therefore, we can write
$V\alpha \dfrac{1}{r}$
This suggests that electric potentials due to point charge are the same for all equidistant points. the locus of these equidistant points, which are at same potential, form a sphere surface.
Hence, the equipotential at a great distance from a collection of charges whose total sum is not zero are spheres.
Option (A) is correct.
Note The work done in moving a charge between two points in an equipotential surface is zero. If a point charge is moved from point \[{V_A}\] to ${V_B}$ in an equipotential surface, then the work done in moving the charge is given by
\[W = q({V_A} - {V_B})\]
As \[({V_A} - {V_B})\] is equal to zero, the total work done is $W = 0$ .
Complete Step by step solution
In this problem, the collection of charges, whose total sum is not zero, with regard to great distance can be considered as a point charge.
Now we know that the electric potential due to point charges $q$ is given by
$V = {k_e}\dfrac{q}{r}$
Since, ${k_e}$ and $q$ are constant
Therefore, we can write
$V\alpha \dfrac{1}{r}$
This suggests that electric potentials due to point charge are the same for all equidistant points. the locus of these equidistant points, which are at same potential, form a sphere surface.
Hence, the equipotential at a great distance from a collection of charges whose total sum is not zero are spheres.
Option (A) is correct.
Note The work done in moving a charge between two points in an equipotential surface is zero. If a point charge is moved from point \[{V_A}\] to ${V_B}$ in an equipotential surface, then the work done in moving the charge is given by
\[W = q({V_A} - {V_B})\]
As \[({V_A} - {V_B})\] is equal to zero, the total work done is $W = 0$ .
Recently Updated Pages
Algebra Made Easy: Step-by-Step Guide for Students

JEE Isolation, Preparation and Properties of Non-metals Important Concepts and Tips for Exam Preparation

JEE Energetics Important Concepts and Tips for Exam Preparation

Chemical Properties of Hydrogen - Important Concepts for JEE Exam Preparation

JEE General Topics in Chemistry Important Concepts and Tips

JEE Amino Acids and Peptides Important Concepts and Tips for Exam Preparation

Trending doubts
JEE Main 2026: Exam Dates, Session 2 Updates, City Slip, Admit Card & Latest News

JEE Main Participating Colleges 2026 - A Complete List of Top Colleges

Kinematics Mock Test for JEE Main 2025-26: Comprehensive Practice

Understanding the Electric Field of a Uniformly Charged Ring

Derivation of Equation of Trajectory Explained for Students

Understanding Atomic Structure for Beginners

Other Pages
CBSE Class 12 Physics Question Paper 2026: Download SET-wise PDF with Answer Key & Analysis

JEE Advanced 2026 Notification Out with Exam Date, Registration (Extended), Syllabus and More

JEE Advanced Percentile vs Marks 2026: JEE Main Cutoff, AIR & IIT Admission Guide

JEE Advanced 2026 Marks vs Rank: Estimate IIT Rank from Your Score

JEE Advanced Weightage Chapter Wise 2026 for Physics, Chemistry, and Mathematics

How to Convert a Galvanometer into an Ammeter or Voltmeter

