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Atomic number of Ag is 47. In the same group, the atomic numbers of elements placed above and below Ag in Long form of periodic table will be:
(A) 26, 95
(B) 39,79
(C) 29,79
(D) 39,65

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Answer
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Hint: We all know about long forms of periodic table. It is also known by the name of Modern periodic table. The periodic table is structured as an \[18\times 7\] grid. We should know that from period four, there are 18 elements in each period.

Complete step by step answer:
We should know that periodic table elements are listed in order of increasing atomic number from left to right. Each row of the periodic table is called a period and each column of the periodic table is called a group (or family). We should note that in periodic tables the elements are arranged in seven horizontal rows, called periods or series, and 18 vertical columns, called groups. The periods are numbered from one to seven on the left-hand side of the table. Some groups have specific names like the halogens or noble gases. Elements within the same period or group have similar properties. When we observe the periodic table, and focus on horizontal rows that are called periods. We got to know that in period one there are two elements. In period two and three, there are eight elements each. In period four and five there are eighteen elements. In period six and seven there is also addition of lanthanides and actinides elements. Lanthanides and actinides are placed separately to fit the periodic table one page.
So, from this above paragraph we can say that we can find the atomic numbers of elements that are placed above and below silver by using one simple concept. To tell the answer we should know that silver whose atomic number is 47 is placed in period five of the periodic table. We should know that, in the periodic table from group four there are 18 elements in each row or period. To find the atomic number of elements above and below of silver we just have to do addition and subtraction of number 18.
So, it should be done as follows:
The atomic number of element above Ag = atomic number of Ag - 18 = 47 - 18 = 29
The atomic number of element below Ag = atomic number of Ag +32 = 47 +32 = 79
So, the correct option is option C.
Atomic number 29 is copper and it is period four.
Atomic number 79 is of gold and it is of period six.

Note:We should know that elements in the same group of the periodic table have similar chemical properties. We classify elements as metals, metalloids, and nonmetals, or as transition metals, and inner transition metals. We number groups from 1–18 from left to right. We should know that elements in group 1 are known as the alkali metals; in group 2 are the alkaline earth metals; in 16 are called chalcogens; those in 17 are the halogens; and those in 18 are the noble gases.