At what angles for the first order diffraction, spacing between two planes, respectively, are $\lambda $ and $\dfrac{\lambda }{2}$ ?
(A) ${0^ \circ },{90^ \circ }$
(B) ${90^ \circ },{0^ \circ }$
(C) ${30^ \circ },{90^ \circ }$
(D) ${90^ \circ },{30^ \circ }$
Answer
265.5k+ views
Hint: The equation that relates the interplanar distance and the angle of diffraction is the Bragg’s equation and it can be given as
\[2d\sin \theta = n\lambda \]
Complete step by step solution:
Bragg’s law gives the angles for the coherent and incoherent scattering of light from a crystal lattice. We know that in crystalline solid, the light waves are scattered from the lattice planes which are separated by the interplanar distance d.
- Scientist Bragg gave the relation between the path differences between the two waves undergo interference and diffraction angle. The Bragg’s equation is given as
\[2d\sin \theta = n\lambda \]
Where d is interplanar distance and n is a positive integer. $\lambda $ is the wavelength of the incident wave.
- We are provided with the question that the diffraction is of first order. So, the value of n is 1.
- Now, in one case, we are given that the interplanar distance is $\lambda $. So, in that case, the Bragg equation will be
\[2d\sin \theta = n\lambda \]
Putting the available values, we will get
\[2\lambda \sin \theta = (1)\lambda \]
So,
\[\sin \theta = \dfrac{\lambda }{{2\lambda }} = \dfrac{1}{2}\]
So, we can say that $\sin {30^ \circ } = \dfrac{1}{2}$ .
So, $\theta = {30^ \circ }$
In the second case, we are given that the interplanar distance is $\dfrac{\lambda }{2}$. So, putting this in the Bragg’s equation will give
\[2\left( {\dfrac{\lambda }{2}} \right)\sin \theta = (1)\lambda \]
So, we can write that
\[\sin \theta = \dfrac{{2\lambda }}{{2\lambda }} = 1\]
Thus, $\sin {90^ \circ } = 1$
So, we got that $\theta = {90^ \circ }$
Thus, we obtained that the angles will be ${30^ \circ }{\text{ and 9}}{{\text{0}}^ \circ }$ respectively.
Therefore, the correct answer is (C).
Note: Note that in the equation, n is the order of diffraction and it is always an integer value. With Bragg's law, we can find the lattice spacing for different cubic lattice systems which also includes the use of Miller indices.
\[2d\sin \theta = n\lambda \]
Complete step by step solution:
Bragg’s law gives the angles for the coherent and incoherent scattering of light from a crystal lattice. We know that in crystalline solid, the light waves are scattered from the lattice planes which are separated by the interplanar distance d.
- Scientist Bragg gave the relation between the path differences between the two waves undergo interference and diffraction angle. The Bragg’s equation is given as
\[2d\sin \theta = n\lambda \]
Where d is interplanar distance and n is a positive integer. $\lambda $ is the wavelength of the incident wave.
- We are provided with the question that the diffraction is of first order. So, the value of n is 1.
- Now, in one case, we are given that the interplanar distance is $\lambda $. So, in that case, the Bragg equation will be
\[2d\sin \theta = n\lambda \]
Putting the available values, we will get
\[2\lambda \sin \theta = (1)\lambda \]
So,
\[\sin \theta = \dfrac{\lambda }{{2\lambda }} = \dfrac{1}{2}\]
So, we can say that $\sin {30^ \circ } = \dfrac{1}{2}$ .
So, $\theta = {30^ \circ }$
In the second case, we are given that the interplanar distance is $\dfrac{\lambda }{2}$. So, putting this in the Bragg’s equation will give
\[2\left( {\dfrac{\lambda }{2}} \right)\sin \theta = (1)\lambda \]
So, we can write that
\[\sin \theta = \dfrac{{2\lambda }}{{2\lambda }} = 1\]
Thus, $\sin {90^ \circ } = 1$
So, we got that $\theta = {90^ \circ }$
Thus, we obtained that the angles will be ${30^ \circ }{\text{ and 9}}{{\text{0}}^ \circ }$ respectively.
Therefore, the correct answer is (C).
Note: Note that in the equation, n is the order of diffraction and it is always an integer value. With Bragg's law, we can find the lattice spacing for different cubic lattice systems which also includes the use of Miller indices.
Recently Updated Pages
JEE Main Mock Test 2025-26: Principles Related To Practical

JEE Main 2025-26 Organic Compounds Containing Nitrogen Mock Test

JEE Main Chemical Kinetics Mock Test 2025-26: Free Practice Online

JEE Main 2025-26 Organic Compounds Containing Oxygen Mock Test

JEE Main 2025-26 Mock Test: Organic Compounds Containing Oxygen

JEE Main 2025-26 Organic Compounds Containing Halogens Mock Test

Trending doubts
JEE Main 2026: Exam Dates, Session 2 Updates, City Slip, Admit Card & Latest News

JEE Main Participating Colleges 2026 - A Complete List of Top Colleges

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Electric Field of a Uniformly Charged Ring

Derivation of Equation of Trajectory Explained for Students

Understanding Atomic Structure for Beginners

Other Pages
JEE Advanced 2026 Notification Out with Exam Date, Registration (Extended), Syllabus and More

JEE Advanced Percentile vs Marks 2026: JEE Main Cutoff, AIR & IIT Admission Guide

CBSE Class 12 Chemistry Question Paper 2026 PDF Download (All Sets) with Answer Key

NCERT Solutions For Class 12 Chemistry Chapter 2 Electrochemistry - 2025-26

NCERT Solutions For Class 12 Chemistry Chapter 1 Solutions - 2025-26

NCERT Solutions For Class 12 Chemistry Chapter 3 Chemical Kinetics - 2025-26

