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Arrange in basic order of their basic strength
I.
II.
III.
IV.

(a) I>II>III>IV
(b) II>III>I>IV
(c) IV>I>III>II
(d) IV>I>II>III

seo-qna
Last updated date: 21st Apr 2024
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Answer
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Hint: Basicity can be referred to as "electron pair instability", and this electron pair instability increases as the charge density on the aniline increases. This means that the basicity should or does increase with the increased negative charge on the group.

Complete answer:
Now we know that basicity increases with the charge density on the group, therefore, we can say that a conjugate base of an amine always be stronger than the amine itself. This relationship between the lower basicity due to the lower charge densities also applies to the lone pairs that are being localised into a larger pi system through resonance.
Thus, we can say that the stronger the acid, the weaker the conjugate base or vice versa.
* In case of the given question, if an electron withdrawing group is attached to amine like ${C}_{6}{H}_{5}$- groups, they decrease the electron density on the nitrogen atom hence decreasing the basicity.
* Further, the effect of an electron withdrawing group like, $N{O}_{2}$, $CN$, $C{H}_{3}$, near to a basic center decreases the basicity due to the electron withdrawing inductive effect.
* Now, among the groups $N{O}_{2}$, $CN$, $C{H}_{3}$, $C{H}_{3}$ has the least electron withdrawing capacity and hence has more basic strength than $N{O}_{2}$, $CN$.
* Among $N{O}_{2}$, $CN$, $N{O}_{2}$ has more electron withdrawing capacity than $CN$, but it also shows resonance in its structure which provides stabilization hereby decreasing the basicity. Thus, $CN$ has more basic strength than $N{O}_{2}$.
Therefore, the correct order of the basic strength is IV>I>III>II. Hence (c) is the correct answer

Note: When a nitro group is present at the o or p-positions then the electron withdrawal is increased for the interaction of the unshared pair electron of nitrogen in the amino group with the benzene nucleus having delocalised p orbital.