
An organic liquid A, containing C,H and O, has a pleasant odour with the boiling point of ${78^ \circ }C$. Upon boiling A with conc. ${H_2}S{O_4}$, a colourless gas B is produced which decolourise bromine water and alkaline $KMn{O_4}$. The organic liquid A is:
(A) $C{H_3}OH$
(B) ${C_2}{H_5}CHO$
(C) ${C_2}{H_6}$
(D) ${C_2}{H_5}OH$
Answer
134.7k+ views
Hint: The compounds that have alcohol group (-OH) may have pleasant odour. All the compounds that have unsaturation in their structure decolourised both bromine water and alkaline potassium permanganate solution.
Complete step by step solution:
We will see all the characteristics of the compound given in the question and find which compound gives that.
- It is given that the organic liquid having C, H and O atoms has a pleasant odour. So, the functional group present in the compound can be alcohol group (-OH).
- It is given that the compound gives a colourless gas upon boiling it with concentrated sulphuric acid. Out of all the given compounds, the one which gives a gas upon an easy reaction with concentrated sulphuric acid is ethanol. The reaction is,
\[{C_2}{H_5}OH\xrightarrow[{ - {H_2}O}]{{{H_2}S{O_4}}}{H_2}C = C{H_2}\]
Thus, we can see that ethene is produced by the dehydration reaction of ethanol. We know that concentrated sulphuric acid is a strong dehydrating agent. Ethene is a colourless gas.
- More importantly ethene decolourise the bromine water as well as alkaline $KMn{O_4}$ solution. It gives this reaction because unsaturation is present in ethene as a C-C double bond is there. So, any compound that has unsaturation gives a decolourization reaction with bromine water and potassium permanganate.
- The boiling point of ethanol is also ${78^ \circ }C$.
Thus, we can say that the compound A is ethanol (${C_2}{H_5}OH$).
So, the correct answer is (D).
Note: Any alcohol when allowed to react with concentrated sulphuric acid will lose a molecule of water and form a C-C double bond. This reaction involves loss of a water molecule from the substrate so it is also called dehydration reaction.
Complete step by step solution:
We will see all the characteristics of the compound given in the question and find which compound gives that.
- It is given that the organic liquid having C, H and O atoms has a pleasant odour. So, the functional group present in the compound can be alcohol group (-OH).
- It is given that the compound gives a colourless gas upon boiling it with concentrated sulphuric acid. Out of all the given compounds, the one which gives a gas upon an easy reaction with concentrated sulphuric acid is ethanol. The reaction is,
\[{C_2}{H_5}OH\xrightarrow[{ - {H_2}O}]{{{H_2}S{O_4}}}{H_2}C = C{H_2}\]
Thus, we can see that ethene is produced by the dehydration reaction of ethanol. We know that concentrated sulphuric acid is a strong dehydrating agent. Ethene is a colourless gas.
- More importantly ethene decolourise the bromine water as well as alkaline $KMn{O_4}$ solution. It gives this reaction because unsaturation is present in ethene as a C-C double bond is there. So, any compound that has unsaturation gives a decolourization reaction with bromine water and potassium permanganate.
- The boiling point of ethanol is also ${78^ \circ }C$.
Thus, we can say that the compound A is ethanol (${C_2}{H_5}OH$).
So, the correct answer is (D).
Note: Any alcohol when allowed to react with concentrated sulphuric acid will lose a molecule of water and form a C-C double bond. This reaction involves loss of a water molecule from the substrate so it is also called dehydration reaction.
Recently Updated Pages
JEE Main 2025 Session 2 Form Correction (Closed) – What Can Be Edited

What are examples of Chemical Properties class 10 chemistry JEE_Main

JEE Main 2025 Session 2 Schedule Released – Check Important Details Here!

JEE Main 2025 Session 2 Admit Card – Release Date & Direct Download Link

JEE Main 2025 Session 2 Registration (Closed) - Link, Last Date & Fees

JEE Mains Result 2025 NTA NIC – Check Your Score Now!

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility, & More

JEE Main 2025: Conversion of Galvanometer Into Ammeter And Voltmeter in Physics

JEE Main 2025: Derivation of Equation of Trajectory in Physics

Degree of Dissociation and Its Formula With Solved Example for JEE

Electric Field Due to Uniformly Charged Ring for JEE Main 2025 - Formula and Derivation

Elastic Collisions in One Dimension - JEE Important Topic

Other Pages
NCERT Solutions for Class 12 Chemistry Chapter 6 Haloalkanes and Haloarenes

NCERT Solutions for Class 12 Chemistry Chapter 2 Electrochemistry

NCERT Solutions for Class 12 Chemistry Chapter 7 Alcohol Phenol and Ether

NCERT Solutions for Class 12 Chemistry Chapter 1 Solutions

Solutions Class 12 Notes: CBSE Chemistry Chapter 1

Electrochemistry Class 12 Notes: CBSE Chemistry Chapter 2
