
Among the following gases which one has the lowest root mean square velocity at \[25^\circ {\rm{C}}\] ?
(1) \[{\rm{S}}{{\rm{O}}_{\rm{2}}}\]
(2) \[{{\rm{N}}_{\rm{2}}}\]
(3) \[{{\rm{O}}_{\rm{2}}}\]
(4) \[{\rm{C}}{{\rm{l}}_{\rm{2}}}\]
Answer
221.7k+ views
Hint: We know the formula of Root mean square(rms) velocity, that is, \[{v_{rms}} = \sqrt {\dfrac{{3RT}}{M}} \] , where, R stands for gas constant, T stands for temperature, M stands for molar mass of the gas. Now, using the formula of RMS speed, we have to compare the rms speeds of the given gases considering the molar mass values of these gases.
Complete Step by Step Solution:
In the given question, using the root rms velocity formula we can identify the gas having lowest rms speed.
rms velocity can be find out by the following formula,
\[{v_{rms}} = \sqrt {\dfrac{{3RT}}{M}} \]
Here, given a set of gases, we have to identify the gas which possesses maximum rms speed.
As R is gas constant and given that all gases are at same temperature, molar masses of each gas decide its rms speed.
So, \[{v_{rms}} = \sqrt {\dfrac{1}{M}} \], that means, rms velocity is indirectly proportional to molar mass of gases. So, the gas that possesses the highest molar mass has the lowest rms velocity.
So, now we will calculate the molar mass of each gas one by one.
Molar mass of \[{\rm{S}}{{\rm{O}}_{\rm{2}}} = 32 + 2 \times 16 = 32 + 32 = 64\,{\rm{u}}\]
Molar mass of \[{{\rm{N}}_{\rm{2}}} = 14 \times 2 = 28\,{\rm{u}}\]
Molar mass of \[{{\rm{O}}_{\rm{2}}} = 16 \times 2 = 32\,{\rm{u}}\]
Molar mass of \[{\rm{C}}{{\rm{l}}_{\rm{2}}} = 35.5 \times 2 = 71\,{\rm{u}}\]
As we have seen, chlorine gas possesses the highest molar mass among all the gases. Therefore, chlorine gas possesses lowest rms velocity.
Hence, option (4) is right.
Note: It is to be noted that average velocity is different from rms velocity. Average velocity defines the arithmetic mean calculation of velocities of different gaseous molecules at a particular temperature. The average velocity can be found by the formula \[{v_{av}} = \sqrt {\dfrac{{8RT}}{{\pi M}}} \] . The rms velocity is always greater than average velocity.
Complete Step by Step Solution:
In the given question, using the root rms velocity formula we can identify the gas having lowest rms speed.
rms velocity can be find out by the following formula,
\[{v_{rms}} = \sqrt {\dfrac{{3RT}}{M}} \]
Here, given a set of gases, we have to identify the gas which possesses maximum rms speed.
As R is gas constant and given that all gases are at same temperature, molar masses of each gas decide its rms speed.
So, \[{v_{rms}} = \sqrt {\dfrac{1}{M}} \], that means, rms velocity is indirectly proportional to molar mass of gases. So, the gas that possesses the highest molar mass has the lowest rms velocity.
So, now we will calculate the molar mass of each gas one by one.
Molar mass of \[{\rm{S}}{{\rm{O}}_{\rm{2}}} = 32 + 2 \times 16 = 32 + 32 = 64\,{\rm{u}}\]
Molar mass of \[{{\rm{N}}_{\rm{2}}} = 14 \times 2 = 28\,{\rm{u}}\]
Molar mass of \[{{\rm{O}}_{\rm{2}}} = 16 \times 2 = 32\,{\rm{u}}\]
Molar mass of \[{\rm{C}}{{\rm{l}}_{\rm{2}}} = 35.5 \times 2 = 71\,{\rm{u}}\]
As we have seen, chlorine gas possesses the highest molar mass among all the gases. Therefore, chlorine gas possesses lowest rms velocity.
Hence, option (4) is right.
Note: It is to be noted that average velocity is different from rms velocity. Average velocity defines the arithmetic mean calculation of velocities of different gaseous molecules at a particular temperature. The average velocity can be found by the formula \[{v_{av}} = \sqrt {\dfrac{{8RT}}{{\pi M}}} \] . The rms velocity is always greater than average velocity.
Recently Updated Pages
Types of Solutions in Chemistry: Explained Simply

States of Matter Chapter For JEE Main Chemistry

Know The Difference Between Fluid And Liquid

Difference Between Crystalline and Amorphous Solid: Table & Examples

Conduction Explained: Definition, Examples & Science for Students

Balancing of Redox Reactions - Important Concepts and Tips for JEE

Trending doubts
JEE Main 2026: Application Form Open, Exam Dates, Syllabus, Eligibility & Question Papers

Derivation of Equation of Trajectory Explained for Students

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Angle of Deviation in a Prism

How to Convert a Galvanometer into an Ammeter or Voltmeter

Degree of Dissociation: Meaning, Formula, Calculation & Uses

Other Pages
NCERT Solutions For Class 11 Chemistry Chapter 7 Redox Reaction

JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Hydrocarbons Class 11 Chemistry Chapter 9 CBSE Notes - 2025-26

Thermodynamics Class 11 Chemistry Chapter 5 CBSE Notes - 2025-26

NCERT Solutions ForClass 11 Chemistry Chapter Chapter 5 Thermodynamics

Equilibrium Class 11 Chemistry Chapter 6 CBSE Notes - 2025-26

