
Aluminium oxide contains \[52.9\% \] aluminium and carbon dioxide contains \[27.27\% \] carbon. Assuming that the law of Reciprocal proportions is true, calculate the percentage of aluminium in aluminium carbide.
Answer
232.5k+ views
Hint: To answer this question we must have the knowledge of the law of reciprocal proportion. These both elements combine with oxygen and then with each other, so the ratio of their mass will remain the same.
Complete step by step solution:
Let us first look at the definition of law of reciprocal proportion:
If element A combines with element B and also with element C, then, if B and C combine together, the proportion by weight in which they do so will be related to the weights of B and C which separately combine with a constant weight of A.
In our question element A is oxygen that combines with both element B and C that is aluminium and carbon respectively to form aluminium oxide and carbon dioxide. Then element B and C combine together to form aluminium carbide. So this fits well will the statement of law and hence the ratio in which they combine will be the same as they combine with A.
let us for the amount of oxygen 1 g. Percentage of aluminium in aluminium oxide is \[52.9\% \], hence the percentage of oxygen will be \[100 - 52.9\% = 47.1\% \]. That means,
\[47.1{\text{ g}}\] of oxygen combined with \[52.9{\text{ g}}\] of aluminium.
1 g of oxygen will combine with \[\dfrac{{52.9}}{{47.1}}{\text{ g }} = 1.123{\text{ g}}\] of aluminium
Percentage of carbon in carbon dioxide is \[27.27\% \], hence the percentage of oxygen will be \[100 - 27.27\% = 72.73\% \]. That means,
\[{\text{72}}{\text{.73 g}}\] of oxygen combined with \[27.27{\text{ g}}\] of carbon.
1 g of oxygen will combine with \[\dfrac{{27.27}}{{72.73}}{\text{ g }} = 0.375{\text{ g}}\] of carbon.
Hence the ratio of aluminium : carbon will be \[1.123:0.375\] and it will be same in aluminium carbide as well,
\[{\text{percentage of Al in aluminium carbide}} = \dfrac{{1.123}}{{1.123 + 0.375}} \times 100\]
Solving this we get:
\[{\text{percentage of Al in aluminium carbide}} = \dfrac{{1.123}}{{1.498}} \times 100 = 75\% \]
Hence, the answer is \[75\% \] .
Note: The law of reciprocal proportion was designed by Jeremias Richter. He used this law for the neutralization of the ratio of metal with acid. As we have calculated the percentage of aluminium we can calculate the percentage of carbon by subtracting the percentage of aluminium from 100.
Complete step by step solution:
Let us first look at the definition of law of reciprocal proportion:
If element A combines with element B and also with element C, then, if B and C combine together, the proportion by weight in which they do so will be related to the weights of B and C which separately combine with a constant weight of A.
In our question element A is oxygen that combines with both element B and C that is aluminium and carbon respectively to form aluminium oxide and carbon dioxide. Then element B and C combine together to form aluminium carbide. So this fits well will the statement of law and hence the ratio in which they combine will be the same as they combine with A.
let us for the amount of oxygen 1 g. Percentage of aluminium in aluminium oxide is \[52.9\% \], hence the percentage of oxygen will be \[100 - 52.9\% = 47.1\% \]. That means,
\[47.1{\text{ g}}\] of oxygen combined with \[52.9{\text{ g}}\] of aluminium.
1 g of oxygen will combine with \[\dfrac{{52.9}}{{47.1}}{\text{ g }} = 1.123{\text{ g}}\] of aluminium
Percentage of carbon in carbon dioxide is \[27.27\% \], hence the percentage of oxygen will be \[100 - 27.27\% = 72.73\% \]. That means,
\[{\text{72}}{\text{.73 g}}\] of oxygen combined with \[27.27{\text{ g}}\] of carbon.
1 g of oxygen will combine with \[\dfrac{{27.27}}{{72.73}}{\text{ g }} = 0.375{\text{ g}}\] of carbon.
Hence the ratio of aluminium : carbon will be \[1.123:0.375\] and it will be same in aluminium carbide as well,
\[{\text{percentage of Al in aluminium carbide}} = \dfrac{{1.123}}{{1.123 + 0.375}} \times 100\]
Solving this we get:
\[{\text{percentage of Al in aluminium carbide}} = \dfrac{{1.123}}{{1.498}} \times 100 = 75\% \]
Hence, the answer is \[75\% \] .
Note: The law of reciprocal proportion was designed by Jeremias Richter. He used this law for the neutralization of the ratio of metal with acid. As we have calculated the percentage of aluminium we can calculate the percentage of carbon by subtracting the percentage of aluminium from 100.
Recently Updated Pages
JEE Main 2023 April 6 Shift 1 Question Paper with Answer Key

JEE Main 2023 April 6 Shift 2 Question Paper with Answer Key

JEE Main 2023 (January 31 Evening Shift) Question Paper with Solutions [PDF]

JEE Main 2023 January 30 Shift 2 Question Paper with Answer Key

JEE Main 2023 January 25 Shift 1 Question Paper with Answer Key

JEE Main 2023 January 24 Shift 2 Question Paper with Answer Key

Trending doubts
JEE Main 2026: Session 2 Registration Open, City Intimation Slip, Exam Dates, Syllabus & Eligibility

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

JEE Main Marking Scheme 2026- Paper-Wise Marks Distribution and Negative Marking Details

Understanding the Angle of Deviation in a Prism

Hybridisation in Chemistry – Concept, Types & Applications

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Hydrocarbons Class 11 Chemistry Chapter 9 CBSE Notes - 2025-26

Thermodynamics Class 11 Chemistry Chapter 5 CBSE Notes - 2025-26

Equilibrium Class 11 Chemistry Chapter 6 CBSE Notes - 2025-26

Organic Chemistry Some Basic Principles And Techniques Class 11 Chemistry Chapter 8 CBSE Notes - 2025-26

NCERT Solutions For Class 11 Chemistry Chapter 7 Redox Reactions (2025-26)

