Question

Addition of conc. HCl to saturated BaCl2 solution precipitates BaCl2; because
A . It follows Le Chatelier principle
B . Of common ion effect
C . Ionic product of [Ba2+][Cl-]2 is constant in a saturated solution.
D . At constant temperature the product [Ba2+][Cl-]2 remains constant in a saturated solution.

Answer 1

Hint: In this question we have to use the concept of precipitation. The precipitate is an insoluble solid, as we are well aware. It originates in a fluid solution. Precipitation describes the process through which an insoluble solid emerges from a liquid solution. It could also be viewed as a suspension. When two soluble salts are combined, an insoluble salt results. It's raining right now.

Complete answer:The equilibrium law, commonly known as Le Chatelier's principles, is used to forecast how certain changes will affect a system in chemical equilibrium (such as the change in temperature or pressure).
According to Le Chatelier, equilibrium modifies the forward and backward reflexes to accommodate changes that influence the equilibrium conditions.
When equilibrium-affecting variables like concentration, pressure, temperature, and inert gases change, the equilibrium will move in a way that cancels out the consequences of the change.
Le Chatelier's techniques are frequently applied to control reversible processes to produce desired results (such as an improvement in yield).

A common ion-containing substance is added, which reduces the solubility of the solute. This is so that the reaction can relax from the stress of the excess product, according to Le Chatelier's principle, which stipulates the reaction will shift to the left (toward the reactants).
It is known as the common ion effect. Some solutes precipitate and become insoluble as a result of this action.

In the question given, both HCl and BaCl2 have Cl-common ions, and thus BaCl2 precipitates.

The correct answer is C.

Note: The drop in temperature is another factor in precipitate formation. Precipitation happens when the temperature is reduced because the solubility lowers. Sulfate ions can be found using this kind of reaction. A specific ion's existence in a solution can be determined using the precipitation reaction. We can therefore make salt from another salt by understanding the solubility of particular salts.