Answer
64.8k+ views
Hint: First draw the circuit diagram and then use KVL to solve the sum.
Electromotive force is defined as the electric potential produced by changing the magnetic field. It is independent of circuit resistance.
Voltmeter is an instrument used for measuring the voltage and ammeter is an instrument used for measuring the current.
Here the cells are connected in series so current flows through each cell.
Complete step by step answer: Let us draw a circuit diagram for solving the given question.
The current$(I)$ is flowing from the positive terminal of the ideal cell to the negative terminal. It is said that the cell is ideal so it has negligible internal resistance. On the other hand, the voltmeter and ammeter are not ideal so they will have internal resistances.
Let ${r_V}$and ${r_A}$be the internal resistances of the voltmeter and ammeter respectively.
Now we will check which of the given statements are correct.
The first statement says that $V < E$. To check this, we apply Kirchhoff’s Voltage law and get the following relation:
$E - I{r_A} - I{r_V} = 0$ $eqn.1$
$ \Rightarrow E = I{r_A} + I{r_V}$
$ \Rightarrow E = {V_A} + V$ $eqn.2$
where ${V_A}$is the voltage drop across ammeter and $V$is the voltage drop across the voltmeter or the reading of the voltmeter.
As, $E$is a summation of ${V_A}$and $V$so, it is clear that $V < E$. Thus, the first statement is correct.
The second statement states that the voltmeter resistance is $\dfrac{V}{I}$.This statement is the mathematical representation of Ohm’s law. So, the second statement is correct.
If we refer to $eqn.2$ we get, ${V_A} = E - V$ , where ${V_A}$is the voltage drop or the potential difference across ammeter . So, the third statement that says the potential difference across the ammeter is $E - V$is correct.
From $eqn.1$we get,
$I{r_A} + I{r_V} = E$
$ \Rightarrow \left( {{r_A} + {r_V}} \right) = \dfrac{E}{I}$
Thus, it is correctly stated in the fourth statement that Voltmeter resistance plus ammeter resistance $ = \dfrac{E}{I}$.
Since all the statements are correct, option D is the correct answer to the question.
Note: Kirchhoff’s voltage law states that the sum of all the voltage in a circuit loop is zero. One of the main disadvantages of connecting the cells in series is that if one component of circuit fails then all the components in the circuits will fail and another disadvantage is that as the number of components in the circuits increases the net resistance of the circuit will also increase.
Electromotive force is defined as the electric potential produced by changing the magnetic field. It is independent of circuit resistance.
Voltmeter is an instrument used for measuring the voltage and ammeter is an instrument used for measuring the current.
Here the cells are connected in series so current flows through each cell.
Complete step by step answer: Let us draw a circuit diagram for solving the given question.
![](https://www.vedantu.com/question-sets/3b9902e6-fa47-4d53-83be-20f4400666438789287822551612309.png)
The current$(I)$ is flowing from the positive terminal of the ideal cell to the negative terminal. It is said that the cell is ideal so it has negligible internal resistance. On the other hand, the voltmeter and ammeter are not ideal so they will have internal resistances.
Let ${r_V}$and ${r_A}$be the internal resistances of the voltmeter and ammeter respectively.
Now we will check which of the given statements are correct.
The first statement says that $V < E$. To check this, we apply Kirchhoff’s Voltage law and get the following relation:
$E - I{r_A} - I{r_V} = 0$ $eqn.1$
$ \Rightarrow E = I{r_A} + I{r_V}$
$ \Rightarrow E = {V_A} + V$ $eqn.2$
where ${V_A}$is the voltage drop across ammeter and $V$is the voltage drop across the voltmeter or the reading of the voltmeter.
As, $E$is a summation of ${V_A}$and $V$so, it is clear that $V < E$. Thus, the first statement is correct.
The second statement states that the voltmeter resistance is $\dfrac{V}{I}$.This statement is the mathematical representation of Ohm’s law. So, the second statement is correct.
If we refer to $eqn.2$ we get, ${V_A} = E - V$ , where ${V_A}$is the voltage drop or the potential difference across ammeter . So, the third statement that says the potential difference across the ammeter is $E - V$is correct.
From $eqn.1$we get,
$I{r_A} + I{r_V} = E$
$ \Rightarrow \left( {{r_A} + {r_V}} \right) = \dfrac{E}{I}$
Thus, it is correctly stated in the fourth statement that Voltmeter resistance plus ammeter resistance $ = \dfrac{E}{I}$.
Since all the statements are correct, option D is the correct answer to the question.
Note: Kirchhoff’s voltage law states that the sum of all the voltage in a circuit loop is zero. One of the main disadvantages of connecting the cells in series is that if one component of circuit fails then all the components in the circuits will fail and another disadvantage is that as the number of components in the circuits increases the net resistance of the circuit will also increase.
Recently Updated Pages
Write a composition in approximately 450 500 words class 10 english JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Arrange the sentences P Q R between S1 and S5 such class 10 english JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
What is the common property of the oxides CONO and class 10 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
What happens when dilute hydrochloric acid is added class 10 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
If four points A63B 35C4 2 and Dx3x are given in such class 10 maths JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
The area of square inscribed in a circle of diameter class 10 maths JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Other Pages
A boat takes 2 hours to go 8 km and come back to a class 11 physics JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Electric field due to uniformly charged sphere class 12 physics JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
In the ground state an element has 13 electrons in class 11 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
According to classical free electron theory A There class 11 physics JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Differentiate between homogeneous and heterogeneous class 12 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Excluding stoppages the speed of a bus is 54 kmph and class 11 maths JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)