
A very high magnetic field is applied to a stationary charge. Then the charge experiences
A.A force in the direction of the magnetic field
B.A force perpendicular to the magnetic field
C.A force in an arbitrary
D.No force
Answer
163.5k+ views
Hint: A very high magnetic field is a vector that describes the magnetic influence of charged particles in a uniform motion. When a charged particle moving relative to the magnetic field experiences a magnetic force, this force is known as the Lorentz force.
Complete answer:
Since when an electric field is stationary, the charged particle does not experience Lorentz force $F$. Even though there is a very high magnetic field applied, there is no magnetic force that acts on motionless charged particles.
Let a charged particle $q$ moves with a uniform velocity $\vec{v}$ in a magnetic field $\vec{B}$ the Lorentz force $\vec{F}$ experienced by particles can be expressed as:
$\vec{F}=q(\vec{v}\times \vec{B})$

Here a magnetic field is applied to a stationary charge, then $\vec{v}=0$
Therefore, the force experienced by a stationary charge is
$\vec{F}=q(0\times \vec{B})$
$\vec{F}=0$
That is, a stationary charge experiences no force in a very high magnetic field.
Thus, Option (D) is correct.
Additional information: Lorentz force only applicable for charged particles like electrons, protons etc. But it can not be applied to neutral particles like neutrons. The neutron’s charge is zero and it does not experience any force in a magnetic field. A neutron particle will traverse undeflected from its path.
Note: If a charged particle moves along the direction of the magnetic field, then the velocity vector is parallel to the magnetic field vector. In that case, the magnetic force experienced by the charged particle is also zero. This is because the angle between the velocity vector and magnetic field vector becomes zero.
Complete answer:
Since when an electric field is stationary, the charged particle does not experience Lorentz force $F$. Even though there is a very high magnetic field applied, there is no magnetic force that acts on motionless charged particles.
Let a charged particle $q$ moves with a uniform velocity $\vec{v}$ in a magnetic field $\vec{B}$ the Lorentz force $\vec{F}$ experienced by particles can be expressed as:
$\vec{F}=q(\vec{v}\times \vec{B})$

Here a magnetic field is applied to a stationary charge, then $\vec{v}=0$
Therefore, the force experienced by a stationary charge is
$\vec{F}=q(0\times \vec{B})$
$\vec{F}=0$
That is, a stationary charge experiences no force in a very high magnetic field.
Thus, Option (D) is correct.
Additional information: Lorentz force only applicable for charged particles like electrons, protons etc. But it can not be applied to neutral particles like neutrons. The neutron’s charge is zero and it does not experience any force in a magnetic field. A neutron particle will traverse undeflected from its path.
Note: If a charged particle moves along the direction of the magnetic field, then the velocity vector is parallel to the magnetic field vector. In that case, the magnetic force experienced by the charged particle is also zero. This is because the angle between the velocity vector and magnetic field vector becomes zero.
Recently Updated Pages
Uniform Acceleration - Definition, Equation, Examples, and FAQs

JEE Main 2021 July 25 Shift 1 Question Paper with Answer Key

JEE Main 2021 July 22 Shift 2 Question Paper with Answer Key

JEE Atomic Structure and Chemical Bonding important Concepts and Tips

JEE Amino Acids and Peptides Important Concepts and Tips for Exam Preparation

JEE Electricity and Magnetism Important Concepts and Tips for Exam Preparation

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility, & More

Atomic Structure - Electrons, Protons, Neutrons and Atomic Models

JEE Main 2025: Derivation of Equation of Trajectory in Physics

Displacement-Time Graph and Velocity-Time Graph for JEE

Electric field due to uniformly charged sphere class 12 physics JEE_Main

Electric Field Due to Uniformly Charged Ring for JEE Main 2025 - Formula and Derivation

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry

Degree of Dissociation and Its Formula With Solved Example for JEE

Wheatstone Bridge for JEE Main Physics 2025

Charging and Discharging of Capacitor

Instantaneous Velocity - Formula based Examples for JEE
