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# A truck is moving under a hopper with a constant speed of 20m/s. Sand falls on the truck at a rate $20kg{s^{ - 1}}$. What is the force acting on the truck due to falling sand?

Last updated date: 14th Apr 2024
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Hint: This numerical problem can be solved by using Newton’s Second law of motion. According to Newton’s second law of motion; Newton's second law states that the acceleration of an object is directly related to the net force and inversely related to its mass. Acceleration of an object depends on two things, force and mass.

Formula Used:
According to the mathematical formulation of Newton’s second law of motion, we know that the force acting is equal to the product of the mass and acceleration of the body. Thus:
$F = m \times a$
In this equation: $m$ is the mass of the body and $a$ is the acceleration of the body.

In this numerical problem it is given that the velocity of the truck is equal to $20m{s^{ - 1}}$. Now, the mass of the sand falling is $20kg$ and the time taken for it to happen is $1\sec$.
Now, the acceleration of the sand is equal to $20m{s^{ - 2}}$.
$F = 20 \times 20 = 400N$
Thus, the force acting on the truck due to the falling sand is equal to $400N$.