
A survey shows that 73% of the persons working in an office like coffee, whereas 65% like tea. If \[x\] denotes the percentage of them who like both coffee and tea. Which is not a value of \[x\]?
A. 63
B. 54
C. 38
D. 36
Answer
161.7k+ views
Hint:We know that \[n\left( U \right) \le n\left( {A \cup B} \right)\] , where \[U\] is the universal set. Then we will apply the formula \[n\left( {A \cup B} \right) = n\left( A \right) + n\left( B \right) - n\left( {A \cap B} \right)\] to calculate the least possible value of \[x\].
Formula Used:
\[n\left( U \right) \le n\left( {A \cup B} \right)\]
\[n\left( {A \cup B} \right) = n\left( A \right) + n\left( B \right) - n\left( {A \cap B} \right)\]
Complete step by step solution:
Let, \[C\] denotes the workers who like coffee.
Let, \[T\] denote the workers who like tea.
Assume that the total number of workers is 100.
The number of workers of like coffee is \[n\left( C \right) = 73\].
The number of workers of like tea is \[n\left( T \right) = 65\].
The number of workers who like both tea and coffee is \[x\].
Applying the formula \[n\left( {A \cup B} \right) = n\left( A \right) + n\left( B \right) - n\left( {A \cap B} \right)\] to calculate \[n\left( {C \cup T} \right)\]
\[n\left( {C \cup T} \right) = n\left( C \right) + n\left( T \right) - n\left( {C \cap T} \right)\]
Substitute the value of \[n\left( C \right)\], \[n\left( T \right)\] and \[n\left( {C \cap T} \right)\]
\[n\left( {C \cup T} \right) = 73 + 65 - x\]
Since the total number of workers is 100. So, \[n\left( {C \cup T} \right) \le 100\]
Therefore, \[73 + 65 - x \le 100\]
Add 73 and 65
\[ \Rightarrow 138 - x \le 100\]
Subtract 138 from both sides of the inequality
\[ \Rightarrow 138 - x - 138 \le 100 - 138\]
\[ \Rightarrow - x \le - 38\]
Multiply -1 on both sides and reverse the inequality sign
\[ \Rightarrow x \ge 38\]
The value of \[x\] is always greater than or equal to 38.
56 and 63 are greater than 38.
But 36 is less than 38.
So 36 is not a solution to the inequality.
Hence option D is the correct option.
Note: Student often do a mistake to solve the inequality \[ - x \le - 38\]. They simply multiply -1 on both sides of the inequality but did not reverse the inequality sign. For this reason, they get an incorrect solution.
Formula Used:
\[n\left( U \right) \le n\left( {A \cup B} \right)\]
\[n\left( {A \cup B} \right) = n\left( A \right) + n\left( B \right) - n\left( {A \cap B} \right)\]
Complete step by step solution:
Let, \[C\] denotes the workers who like coffee.
Let, \[T\] denote the workers who like tea.
Assume that the total number of workers is 100.
The number of workers of like coffee is \[n\left( C \right) = 73\].
The number of workers of like tea is \[n\left( T \right) = 65\].
The number of workers who like both tea and coffee is \[x\].
Applying the formula \[n\left( {A \cup B} \right) = n\left( A \right) + n\left( B \right) - n\left( {A \cap B} \right)\] to calculate \[n\left( {C \cup T} \right)\]
\[n\left( {C \cup T} \right) = n\left( C \right) + n\left( T \right) - n\left( {C \cap T} \right)\]
Substitute the value of \[n\left( C \right)\], \[n\left( T \right)\] and \[n\left( {C \cap T} \right)\]
\[n\left( {C \cup T} \right) = 73 + 65 - x\]
Since the total number of workers is 100. So, \[n\left( {C \cup T} \right) \le 100\]
Therefore, \[73 + 65 - x \le 100\]
Add 73 and 65
\[ \Rightarrow 138 - x \le 100\]
Subtract 138 from both sides of the inequality
\[ \Rightarrow 138 - x - 138 \le 100 - 138\]
\[ \Rightarrow - x \le - 38\]
Multiply -1 on both sides and reverse the inequality sign
\[ \Rightarrow x \ge 38\]
The value of \[x\] is always greater than or equal to 38.
56 and 63 are greater than 38.
But 36 is less than 38.
So 36 is not a solution to the inequality.
Hence option D is the correct option.
Note: Student often do a mistake to solve the inequality \[ - x \le - 38\]. They simply multiply -1 on both sides of the inequality but did not reverse the inequality sign. For this reason, they get an incorrect solution.
Recently Updated Pages
If tan 1y tan 1x + tan 1left frac2x1 x2 right where x frac1sqrt 3 Then the value of y is

Geometry of Complex Numbers – Topics, Reception, Audience and Related Readings

JEE Main 2021 July 25 Shift 1 Question Paper with Answer Key

JEE Main 2021 July 22 Shift 2 Question Paper with Answer Key

JEE Electricity and Magnetism Important Concepts and Tips for Exam Preparation

JEE Energetics Important Concepts and Tips for Exam Preparation

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility, & More

JEE Main 2025: Derivation of Equation of Trajectory in Physics

Displacement-Time Graph and Velocity-Time Graph for JEE

Degree of Dissociation and Its Formula With Solved Example for JEE

Electric Field Due to Uniformly Charged Ring for JEE Main 2025 - Formula and Derivation

JoSAA JEE Main & Advanced 2025 Counselling: Registration Dates, Documents, Fees, Seat Allotment & Cut‑offs

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry

JEE Advanced 2025: Dates, Registration, Syllabus, Eligibility Criteria and More

Verb Forms Guide: V1, V2, V3, V4, V5 Explained

1 Billion in Rupees

Which one is a true fish A Jellyfish B Starfish C Dogfish class 11 biology CBSE
