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**Hint**Electric dipole is defined as a couple of opposite charges q and -q separated by a distance of d. The direction of the electric dipoles in the space is always from negative charge -q to the positive charge q. Based on this concept this question is to be solved.

**Step-by step answer**

The electric field due to a dipole at any point in space is given by,

$E = \dfrac{1}{{\left( {4\pi {\varepsilon _0}{r^3}} \right)\left( {3(\vec p \cdot \hat r)\hat r - p} \right)}}$

So, we can write that:

$r = 2\hat i + 2\sqrt {2j} \Rightarrow \hat r = \dfrac{1}{{\sqrt {3i} }} + \sqrt {\dfrac{2}{3}\hat j}$

The value of $\operatorname{Tan} \theta = \dfrac{y}{x} = \dfrac{{2\sqrt 2 }}{2} = \sqrt 2$

Hence the value of E is given by:

$E = \dfrac{1}{{\left( {4\pi {\varepsilon _0}{r^3}} \right)(\sqrt 3 p\hat rp\hat i)}}$

The i component cancels out leaving only the j component.

Form the figure we can see that:

From the figure,

$\operatorname{Tan} \phi = \cot \theta$ so,

$\phi = 90 - \theta$

Now $\vec E$ is along + y-axis

**Hence, the correct answer is Option B.**

**Note**Electric field is defined as the electric force per unit charge. The direction of the field is taken to be the direction of the force it would exert on a positive test charge. The electric field radially outward from a positive charge and radially in toward a negative point charge.

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