
A set of seven observations has mean ten and another set of three observations has mean five. The mean of the combined set is:
A. 15
B. 10
C. 8.5
D. 7.5
Answer
218.7k+ views
Hint: First of all, determine the sum of the 7 operations and then determine the sum of the 3 operations. After that determine the sum of both the operation 7 and 3. There are 10 total numbers of operations. And then divide the sum of both the operations by the total number of operations. Hence, we will get a suitable answer.
Complete step by step solution:
Let us assume that x and y are the sum of 7 and 3 operations respectively. And we have given that the mean of 7 operations are 10 and the mean of the 3 operations are the 5. Therefore,
We know that if the ${a_1}, {a_2}, {a_3}$ and ${a_n}$ are the integers, then the mean of these numbers is given by,
${ \Rightarrow mean} = {\dfrac{{{a_1} + {a_2} + {a_3}.... + {a_n}}}{n}} $
Now we have the mean of the 7 operations, therefore, we can write.
$ \Rightarrow {10} = {\dfrac{x}{7}} $
$ \Rightarrow x = {70} $
Similarly, for the 3 operations,
$ \Rightarrow y = {15} $
Now the total sum of these operations are,
$ \Rightarrow 70 + 15$
$ \Rightarrow 85$
Therefore the mean of the combined set is ,
$ \Rightarrow \dfrac{{85}}{{10}}$
$ \Rightarrow 8.5$
Now the final answer is 8.5.
Option ‘C’ is correct
Note: Remember that the total sum of the operation is calculated by adding the sum of the 7 and the sum of the 3 operations. The total number of operations is 10. So, to determine the mean of the total number of the operations, we will have to divide the total sum of both the operations by the total number of operations.
Complete step by step solution:
Let us assume that x and y are the sum of 7 and 3 operations respectively. And we have given that the mean of 7 operations are 10 and the mean of the 3 operations are the 5. Therefore,
We know that if the ${a_1}, {a_2}, {a_3}$ and ${a_n}$ are the integers, then the mean of these numbers is given by,
${ \Rightarrow mean} = {\dfrac{{{a_1} + {a_2} + {a_3}.... + {a_n}}}{n}} $
Now we have the mean of the 7 operations, therefore, we can write.
$ \Rightarrow {10} = {\dfrac{x}{7}} $
$ \Rightarrow x = {70} $
Similarly, for the 3 operations,
$ \Rightarrow y = {15} $
Now the total sum of these operations are,
$ \Rightarrow 70 + 15$
$ \Rightarrow 85$
Therefore the mean of the combined set is ,
$ \Rightarrow \dfrac{{85}}{{10}}$
$ \Rightarrow 8.5$
Now the final answer is 8.5.
Option ‘C’ is correct
Note: Remember that the total sum of the operation is calculated by adding the sum of the 7 and the sum of the 3 operations. The total number of operations is 10. So, to determine the mean of the total number of the operations, we will have to divide the total sum of both the operations by the total number of operations.
Recently Updated Pages
In a game two players A and B take turns in throwing class 12 maths JEE_Main

The number of ways in which 6 men and 5 women can dine class 12 maths JEE_Main

The area of an expanding rectangle is increasing at class 12 maths JEE_Main

If y xxx cdots infty then find dfracdydx A yxy 1 B class 12 maths JEE_Main

Chemical Properties of Hydrogen - Important Concepts for JEE Exam Preparation

JEE General Topics in Chemistry Important Concepts and Tips

Trending doubts
JEE Main 2026: Application Form Open, Exam Dates, Syllabus, Eligibility & Question Papers

Derivation of Equation of Trajectory Explained for Students

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Angle of Deviation in a Prism

Understanding Collisions: Types and Examples for Students

Understanding Atomic Structure for Beginners

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

How to Convert a Galvanometer into an Ammeter or Voltmeter

Understanding Centrifugal Force in Physics

JEE Main Marking Scheme 2026- Paper-Wise Marks Distribution and Negative Marking Details

Degree of Dissociation: Meaning, Formula, Calculation & Uses

Understanding Electromagnetic Waves and Their Importance

