Answer
Verified
104.4k+ views
Hint: A Plano-convex lens is a lens which is made by joining a flat plane and a convex lens.
Silvering of flat plane converts it into a mirror as now the light rays will be reflected by the lens instead of passing through after refraction.
The power of a lens is the ability of a lens to converge or diverge a ray of light falling on it.
Complete step by step solution:
The following images show how a Plano-convex lens looks like
Now when its plane part is silvered so it acts as a mirror now, refer the image
Here we can say that it is now a combination of a convex lens and a plane mirror both of which have their powers
The power of a Plano-convex lens is equal to the sum of twice the power of lens and mirror
i.e.,${P_{total}} = 2{P_{lens}} + {P_{mirror}}$
We know that power of a lens is given by ${P_{lens}} = \left( {\dfrac{1}{{{f_{lens}}}}} \right)$
Where ${f_{lens}}$is the focal length of the mirror
And the power of a plane mirror is given by ${P_{mirror}} = \left( {\dfrac{1}{{{f_{mirror}}}}} \right)$
Where ${f_{mirror}}$ is the focal length of the mirror
So total power of the setup will be
\[
\because {P_{total}} = 2{P_{lens}} + {P_{mirror}} \\
\therefore {P_{total}} = 2 \times \left( {\dfrac{1}{{{f_{lens}}}}} \right) + \dfrac{1}{{{f_{mirror}}}} \\
\]
Here the focal length of the lens is given as $20cm$
And we know that the focal length of a plane mirror is $\infty $
Substituting these values in the above equation
\[
{P_{total}} = 2 \times \left( {\dfrac{1}{{20}}} \right) + \dfrac{1}{\infty } \\
\Rightarrow {P_{total}} = \dfrac{1}{{10}} \\
\]
Here we get to know that the power of a plane mirror is zero because a plane mirror neither converges or diverges any ray of light falling on it just reflects them back.
Now as we know that the power is the reciprocal of the focal length so the new focal length corresponding to this power will be,
Let new focal length be $f`$
We know that
\[
{P_{total}} = \dfrac{1}{{f`}} \\
\therefore f` = \dfrac{1}{{{P_{total}}}} \\
\because {P_{total}} = \dfrac{1}{{10}} \\
\therefore f` = 10cm \\
\]
The new focal length of the Plano-convex mirror will be $10cm$.
Note: 1) The power of a lens depends upon its focal length
2) The focal length of a plane mirror is infinity and thus its power is zero
3) Silvering of any lens makes it a mirror because now it will reflect the light rays falling on it
Silvering of flat plane converts it into a mirror as now the light rays will be reflected by the lens instead of passing through after refraction.
The power of a lens is the ability of a lens to converge or diverge a ray of light falling on it.
Complete step by step solution:
The following images show how a Plano-convex lens looks like
Now when its plane part is silvered so it acts as a mirror now, refer the image
Here we can say that it is now a combination of a convex lens and a plane mirror both of which have their powers
The power of a Plano-convex lens is equal to the sum of twice the power of lens and mirror
i.e.,${P_{total}} = 2{P_{lens}} + {P_{mirror}}$
We know that power of a lens is given by ${P_{lens}} = \left( {\dfrac{1}{{{f_{lens}}}}} \right)$
Where ${f_{lens}}$is the focal length of the mirror
And the power of a plane mirror is given by ${P_{mirror}} = \left( {\dfrac{1}{{{f_{mirror}}}}} \right)$
Where ${f_{mirror}}$ is the focal length of the mirror
So total power of the setup will be
\[
\because {P_{total}} = 2{P_{lens}} + {P_{mirror}} \\
\therefore {P_{total}} = 2 \times \left( {\dfrac{1}{{{f_{lens}}}}} \right) + \dfrac{1}{{{f_{mirror}}}} \\
\]
Here the focal length of the lens is given as $20cm$
And we know that the focal length of a plane mirror is $\infty $
Substituting these values in the above equation
\[
{P_{total}} = 2 \times \left( {\dfrac{1}{{20}}} \right) + \dfrac{1}{\infty } \\
\Rightarrow {P_{total}} = \dfrac{1}{{10}} \\
\]
Here we get to know that the power of a plane mirror is zero because a plane mirror neither converges or diverges any ray of light falling on it just reflects them back.
Now as we know that the power is the reciprocal of the focal length so the new focal length corresponding to this power will be,
Let new focal length be $f`$
We know that
\[
{P_{total}} = \dfrac{1}{{f`}} \\
\therefore f` = \dfrac{1}{{{P_{total}}}} \\
\because {P_{total}} = \dfrac{1}{{10}} \\
\therefore f` = 10cm \\
\]
The new focal length of the Plano-convex mirror will be $10cm$.
Note: 1) The power of a lens depends upon its focal length
2) The focal length of a plane mirror is infinity and thus its power is zero
3) Silvering of any lens makes it a mirror because now it will reflect the light rays falling on it
Recently Updated Pages
Write a composition in approximately 450 500 words class 10 english JEE_Main
Arrange the sentences P Q R between S1 and S5 such class 10 english JEE_Main
Write an article on the need and importance of sports class 10 english JEE_Main
Name the scale on which the destructive energy of an class 11 physics JEE_Main
Choose the exact meaning of the given idiomphrase The class 9 english JEE_Main
Choose the one which best expresses the meaning of class 9 english JEE_Main