Answer
Verified
86.7k+ views
Hint The acceleration due to gravity on the surface of the Moon is around \[1.625\;m/{s^2}\] that is about \[16.6\% \]that on Earth's surface.
Complete Step by step solution
So let’s understand the basics.
The force that attracts a body towards the centre of the earth gravitational force
The gravitational force of earth is around $9.8m/s_{}^2$
So in our planet earth, the closer objects are to each other the stronger their gravitational pull is. Earth's gravity comes from all its mass. All its mass makes a combined gravitational pull on all the mass in your body
So you can conclude that you exert the same gravitational force on Earth that it does on you.
While, comparing to earth gravitational force of earth moon have $1.62m/s_{}^2$
The Moon's surface gravity is weaker because it is far less massive than Earth. A body's surface gravity is proportional to its mass, but inversely proportional to the square of its radius.
The mass of the moon is $\dfrac{1}{{100}}$times and its radius $\dfrac{1}{4}$times that of earth.
Hence, the weight of an object on the moon is $\dfrac{1}{6}th$its weight on the earth
So on the moon we are not at all that combined force.
So by this we can logically find that the moon gravitational force is hereby negligible in comparison to earth’s gravitational surface
A person on the surface of the moon does not feel the effect of earth’s gravity.
Hence option c is correct
Additional information
The moon's gravitational pull on the Earth is the main cause of the rise and fall of ocean tides. Where ocean waters face the moon and the pull is strongest and one where ocean waters face away from the moon and the pull is weakest.
Note
First we need to find the gravitational force of both then how it affects the human body
Going through the physical properties and the reason behind the high and low of both the gravitational forces to understand it better.
Complete Step by step solution
So let’s understand the basics.
The force that attracts a body towards the centre of the earth gravitational force
The gravitational force of earth is around $9.8m/s_{}^2$
So in our planet earth, the closer objects are to each other the stronger their gravitational pull is. Earth's gravity comes from all its mass. All its mass makes a combined gravitational pull on all the mass in your body
So you can conclude that you exert the same gravitational force on Earth that it does on you.
While, comparing to earth gravitational force of earth moon have $1.62m/s_{}^2$
The Moon's surface gravity is weaker because it is far less massive than Earth. A body's surface gravity is proportional to its mass, but inversely proportional to the square of its radius.
The mass of the moon is $\dfrac{1}{{100}}$times and its radius $\dfrac{1}{4}$times that of earth.
Hence, the weight of an object on the moon is $\dfrac{1}{6}th$its weight on the earth
So on the moon we are not at all that combined force.
So by this we can logically find that the moon gravitational force is hereby negligible in comparison to earth’s gravitational surface
A person on the surface of the moon does not feel the effect of earth’s gravity.
Hence option c is correct
Additional information
The moon's gravitational pull on the Earth is the main cause of the rise and fall of ocean tides. Where ocean waters face the moon and the pull is strongest and one where ocean waters face away from the moon and the pull is weakest.
Note
First we need to find the gravitational force of both then how it affects the human body
Going through the physical properties and the reason behind the high and low of both the gravitational forces to understand it better.
Recently Updated Pages
Name the scale on which the destructive energy of an class 11 physics JEE_Main
Write an article on the need and importance of sports class 10 english JEE_Main
Choose the exact meaning of the given idiomphrase The class 9 english JEE_Main
Choose the one which best expresses the meaning of class 9 english JEE_Main
What does a hydrometer consist of A A cylindrical stem class 9 physics JEE_Main
A motorcyclist of mass m is to negotiate a curve of class 9 physics JEE_Main
Other Pages
The thickness of the depletion layer is approximately class 11 physics JEE_Main
Velocity of car at t 0 is u moves with a constant acceleration class 11 physics JEE_Main
If a wire of resistance R is stretched to double of class 12 physics JEE_Main
Derive an expression for maximum speed of a car on class 11 physics JEE_Main
Electric field due to uniformly charged sphere class 12 physics JEE_Main