Answer
64.8k+ views
Hint: In this question, we have to find the maximum velocity during the rectilinear motion with acceleration\[a\]. For that we have to find the area under the curve where acceleration \[a\]has the maximum value
Complete step by step answer:
![](https://www.vedantu.com/question-sets/76d8a3e4-814e-4128-b848-9f2174887eae204630404794578758.png)
In this question, we have to find the maximum velocity during the rectilinear motion with acceleration (\[a\])
Since, we know that
\[a = \dfrac{{dv}}{{dt}}\]
Or we can write the above equation as,
\[v = \int {a.dt} \]
Therefore, for finding the maximum velocity we have to find the area under the curve where \[a\]is maximum
As we can see in the graph the maximum value of a is \[10\,m\]/\[s\]
Now, since the graph is in the form of triangle, area under the curve will be, \[\dfrac{1}{2} \times X - axis\, \times \,Y - axis\]
On putting the values we get,
\[\dfrac{1}{2} \times 10\, \times \,12 = 60\]
Hence, the maximum velocity during the rectilinear motion with acceleration (\[a\]) will be \[60\,m\]/\[{s^2}\]
Note: For this type of question, the best method to solve is to find the area under the curve for the required intervals by integration or else we can do it by the normal method as we did in the above question.
Complete step by step answer:
![](https://www.vedantu.com/question-sets/76d8a3e4-814e-4128-b848-9f2174887eae204630404794578758.png)
In this question, we have to find the maximum velocity during the rectilinear motion with acceleration (\[a\])
Since, we know that
\[a = \dfrac{{dv}}{{dt}}\]
Or we can write the above equation as,
\[v = \int {a.dt} \]
Therefore, for finding the maximum velocity we have to find the area under the curve where \[a\]is maximum
As we can see in the graph the maximum value of a is \[10\,m\]/\[s\]
Now, since the graph is in the form of triangle, area under the curve will be, \[\dfrac{1}{2} \times X - axis\, \times \,Y - axis\]
On putting the values we get,
\[\dfrac{1}{2} \times 10\, \times \,12 = 60\]
Hence, the maximum velocity during the rectilinear motion with acceleration (\[a\]) will be \[60\,m\]/\[{s^2}\]
Note: For this type of question, the best method to solve is to find the area under the curve for the required intervals by integration or else we can do it by the normal method as we did in the above question.
Recently Updated Pages
Write a composition in approximately 450 500 words class 10 english JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Arrange the sentences P Q R between S1 and S5 such class 10 english JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
What is the common property of the oxides CONO and class 10 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
What happens when dilute hydrochloric acid is added class 10 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
If four points A63B 35C4 2 and Dx3x are given in such class 10 maths JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
The area of square inscribed in a circle of diameter class 10 maths JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Other Pages
Excluding stoppages the speed of a bus is 54 kmph and class 11 maths JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
In the ground state an element has 13 electrons in class 11 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Electric field due to uniformly charged sphere class 12 physics JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
A boat takes 2 hours to go 8 km and come back to a class 11 physics JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
According to classical free electron theory A There class 11 physics JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Differentiate between homogeneous and heterogeneous class 12 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)