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# A particle moves along a curve of unknown shape, but magnitude of force F is constant and always acts along a tangent to the curve. Then (A) $\overrightarrow F$ may be conservative(B) $\overrightarrow F$ must be conservative(C) $\overrightarrow F$ may be non-conservative(D) $\overrightarrow F$ must be non-conservative

Last updated date: 15th Jun 2024
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Hint: We know that conservative force is path independent and non-conservative forces are path dependent. We must observe the work done by F along a curve to know the nature of the force.

Complete step by step answer We can consider a path and see how much work done if an applied force makes some displacement

As you can see in the diagram, a curve of unknown shape has force F acting along the tangent and is constant, so for small displacement dS,
Hence work done $W = \int\limits_0^S {\overrightarrow F d\overrightarrow S } = \int\limits_0^S {FdS\cos \theta }$ since F is constant.
$\Rightarrow W = F\int\limits_0^S {dS}$so, the work done by force F is dependent on path
From the question we can see that the work done at every point of curve is dependent upon the path followed. If the work done is conservative in nature then, the force acting must be non-conservative.

Hence, option D. $\overrightarrow F$ must be non-conservative.