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# A low-loss transformer has 230V applied to the primary and gives 4.6V in the secondary. The secondary is connected to a load, which draws 50A of current. The current (in ampere) in the primary is: A) 0.1B) 1.0C) 10D) 250

Last updated date: 10th Sep 2024
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Hint: An electric current is defined as the net flow rate of the electric charge. The unit of current is Ampere. It is a stream of charged particles like ions or electrons that are moving through an electrical conductor.

Complete step by step solution:
Given data:
The primary voltage in the transformer, ${V_1} = 230V$
The secondary voltage in the transformer, ${V_2} = 4.6V$
The secondary current, ${I_2} = 50A$
The primary current, ${I_1} = ?$
We know that power must be the same in the primary and the secondary transformers.
Also, power is given by the formula, $P = VI$
$\Rightarrow {V_1}{I_1} = {V_2}{I_2}$
Substituting the values, we get
$\Rightarrow 230 \times {I_1} = 4.6 \times 50$
$\Rightarrow {I_1} = \dfrac{{4.6 \times 50}}{{230}} = 1A$
Thus the primary current, ${I_1} = 1A$

Hence the correct option is B.