
A current of 10A is flowing in a wire of length . A force of acts on it when it is placed in a uniform magnetic field of . The angle between the magnetic field and the direction of the current is:
(A)
(B)
(C)
(D)
Answer
140.7k+ views
Hint: To solve this question, we have to use the formula of the force on a current carrying wire when it is placed in a uniform magnetic field. Then we have to substitute the given values into that formula to get the required value of the angle between the magnetic field and the direction of the current.
Formula used: The formula used to solve this question is given by
, here is the force acting on a wire having a length of and carrying a current of , when it is placed in a uniform magnetic field of .
Complete step by step solution:
Let the angle between the magnetic field be .
We know that the force exerted on a current carrying wire when it is placed in a magnetic field is given by
Writing the magnitudes on both the sides, we get
According to the question, , , , and . Substituting these above, we get
Dividing both the sides by we get
Taking sine inverse both the sides, we finally get
Thus, the angle between the magnetic field and the direction of the current is equal to .
Hence, the correct answer is option A.
Note: Although the cross product which appears in the expression for force on a current carrying wire is between the length and the magnetic field, it is defined between the magnetic field and the direction of current. This is done because we cannot take the cross product of the current as it is a scalar quantity.
Formula used: The formula used to solve this question is given by
Complete step by step solution:
Let the angle between the magnetic field be
We know that the force exerted on a current carrying wire when it is placed in a magnetic field is given by
Writing the magnitudes on both the sides, we get
According to the question,
Dividing both the sides by
Taking sine inverse both the sides, we finally get
Thus, the angle between the magnetic field and the direction of the current is equal to
Hence, the correct answer is option A.
Note: Although the cross product which appears in the expression for force on a current carrying wire is between the length and the magnetic field, it is defined between the magnetic field and the direction of current. This is done because we cannot take the cross product of the current as it is a scalar quantity.
Latest Vedantu courses for you
Grade 10 | CBSE | SCHOOL | English
Vedantu 10 CBSE Pro Course - (2025-26)
School Full course for CBSE students
₹37,300 per year
EMI starts from ₹3,108.34 per month
Recently Updated Pages
Young's Double Slit Experiment Step by Step Derivation

Difference Between Circuit Switching and Packet Switching

Difference Between Mass and Weight

JEE Main Participating Colleges 2024 - A Complete List of Top Colleges

JEE Main Maths Paper Pattern 2025 – Marking, Sections & Tips

Sign up for JEE Main 2025 Live Classes - Vedantu

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility, & More

JEE Main Exam Marking Scheme: Detailed Breakdown of Marks and Negative Marking

JEE Main 2025: Derivation of Equation of Trajectory in Physics

Electric Field Due to Uniformly Charged Ring for JEE Main 2025 - Formula and Derivation

Learn About Angle Of Deviation In Prism: JEE Main Physics 2025

Electric field due to uniformly charged sphere class 12 physics JEE_Main

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry

Degree of Dissociation and Its Formula With Solved Example for JEE

JEE Main 2025: Conversion of Galvanometer Into Ammeter And Voltmeter in Physics

Dual Nature of Radiation and Matter Class 12 Notes: CBSE Physics Chapter 11

Formula for number of images formed by two plane mirrors class 12 physics JEE_Main
