
A car moves from A to B with a speed of $30kmph$ and from B to A with a speed of $20kmph$. What is the average speed of the car?
$\left( A \right)25kmph$
$\left( B \right)24kmph$
$\left( C \right)50kmph$
$\left( D \right)10kmph$
Answer
218.7k+ views
Hint: Here, the rate of change of displacement is called velocity. Average speed of a body undergoing linear motion is the ratio of total distance to total time. It is a scalar quantity. Here the speed to move from A to B and time to move from B to A is given. Using the given data, find the average speed of a car.
Complete step by step answer:
To describe the apposition of a body, its velocity or acceleration relative to frame of reference we use the kinematic equation. Velocity is the rate of change of displacement.
If the motion starts from rest and the frame of reference should be the same, the initial velocity will be zero. If the motion starts from rest and the frame of reference should be the same. It is a scalar quantity.
The body will move in uniform motion in a straight line, when the body is moving with uniform velocity.
Distance to unit time is called speed. Equation integration results in the distance equation.
Let us consider the distance travelled by the car from A to B to be $x$
The time taken by the car from A to B to be $ = \dfrac{x}{{30}}hour$
The time taken by the car from B to A to be $ = \dfrac{x}{{20}}hour$
Then we can calculate the average speed of the car is given by = $\dfrac{{Total{\text{ }}distance}}{{Total{\text{ time}}}}$
$\Rightarrow s = \dfrac{{x + x}}{{\dfrac{x}{{30}} + \dfrac{x}{{20}}}}$
On further simplification we get
Here $\left( {\left( {\dfrac{x}{{30}} + \dfrac{x}{{20}}} \right) = \left( {\dfrac{{2x + 3x}}{{60}}} \right) = \dfrac{x}{{12}}} \right)$
$\Rightarrow s = 2x \times \dfrac{{12}}{x}$
On multiply the term and we get
$\Rightarrow s = 24km/h$
Hence option B is the correct option.
Note: The motion starts from rest and the frame of reference should be the same. Then the initial velocity is zero. The velocity equation integration results in the acceleration equation. Displacement may or may not be equal to the path length travelled of an object. Distance to unit time is called speed.
Complete step by step answer:
To describe the apposition of a body, its velocity or acceleration relative to frame of reference we use the kinematic equation. Velocity is the rate of change of displacement.
If the motion starts from rest and the frame of reference should be the same, the initial velocity will be zero. If the motion starts from rest and the frame of reference should be the same. It is a scalar quantity.
The body will move in uniform motion in a straight line, when the body is moving with uniform velocity.
Distance to unit time is called speed. Equation integration results in the distance equation.
Let us consider the distance travelled by the car from A to B to be $x$
The time taken by the car from A to B to be $ = \dfrac{x}{{30}}hour$
The time taken by the car from B to A to be $ = \dfrac{x}{{20}}hour$
Then we can calculate the average speed of the car is given by = $\dfrac{{Total{\text{ }}distance}}{{Total{\text{ time}}}}$
$\Rightarrow s = \dfrac{{x + x}}{{\dfrac{x}{{30}} + \dfrac{x}{{20}}}}$
On further simplification we get
Here $\left( {\left( {\dfrac{x}{{30}} + \dfrac{x}{{20}}} \right) = \left( {\dfrac{{2x + 3x}}{{60}}} \right) = \dfrac{x}{{12}}} \right)$
$\Rightarrow s = 2x \times \dfrac{{12}}{x}$
On multiply the term and we get
$\Rightarrow s = 24km/h$
Hence option B is the correct option.
Note: The motion starts from rest and the frame of reference should be the same. Then the initial velocity is zero. The velocity equation integration results in the acceleration equation. Displacement may or may not be equal to the path length travelled of an object. Distance to unit time is called speed.
Recently Updated Pages
Two discs which are rotating about their respective class 11 physics JEE_Main

A ladder rests against a frictionless vertical wall class 11 physics JEE_Main

Two simple pendulums of lengths 1 m and 16 m respectively class 11 physics JEE_Main

The slopes of isothermal and adiabatic curves are related class 11 physics JEE_Main

A trolly falling freely on an inclined plane as shown class 11 physics JEE_Main

The masses M1 and M2M2 M1 are released from rest Using class 11 physics JEE_Main

Trending doubts
JEE Main 2026: Application Form Open, Exam Dates, Syllabus, Eligibility & Question Papers

Understanding Uniform Acceleration in Physics

Derivation of Equation of Trajectory Explained for Students

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Angle of Deviation in a Prism

Understanding Collisions: Types and Examples for Students

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Units And Measurements Class 11 Physics Chapter 1 CBSE Notes - 2025-26

NCERT Solutions For Class 11 Physics Chapter 8 Mechanical Properties Of Solids

Motion in a Straight Line Class 11 Physics Chapter 2 CBSE Notes - 2025-26

NCERT Solutions for Class 11 Physics Chapter 7 Gravitation 2025-26

Understanding Atomic Structure for Beginners

