
A bullet is fired from a rifle with a velocity \[750m/s\]. If the length of the rifle barrel is $60cm$. Calculate average velocity of the bullet, while being accelerated in the barrel, Find the time taken by bullet to travel.
Answer
213.9k+ views
Hint: Calculate average velocity, we add initial and final velocity and divide their sum with 2, then to find acceleration we use the third equation of motion, and finally to find out the time taken by a bullet to travel, we use the first equation of motion.
Given:
Length of barrel, $S = 60cm$
As the velocity of bullet is given in $m/s$then, the distance should be in $m$
So, $S = 0.6m$
Final velocity, $V = 750m/s$
Initial velocity, $U = 0$
Formula used:
${V_{avg}} = \dfrac{{U + V}}{2}$
${V^2} = {U^2} + 2aS$
$\dfrac{{V - U}}{T} = a$
Complete Step by step solution:
To calculate the average velocity of the bullet, we use a formula in which the sum of initial and final velocity is divided by 2.
Now, we will calculate the average velocity
${V_{avg}} = \dfrac{{U + V}}{2}$
\[ = \dfrac{{0 + 750}}{2}\](Putting value of $U$and$V$)
$ = 375m/s$
Here we got an average velocity of the bullet which is $375m/s$
Now, you know there is a relationship between initial velocity, final velocity, distance, and acceleration
${V^2} = {U^2} + 2aS$(Here $a$is an acceleration)
${750^2} = 0 + 2a \times 0.6$(Putting values of $U,S$and$V$ )
$a = \dfrac{{562500}}{{1.2}} = 468750 = 46.88 \times {10^4}m/s$
Here we got acceleration, which we can use in the relation of final velocity, initial velocity, acceleration, and time, where we have everything except time, so we will calculate time from this relation.$\dfrac{{V - U}}{T} = a$
After simplification, we can write this equation, as below
$T = \dfrac{{V - U}}{a}$
$ = \dfrac{{750 - 0}}{{46.88 \times {{10}^4}}}$(Putting values of $U,a$and$V$)
$ = 15.998 \times {10^{ - 4}}s$
Here, we have calculated the time taken by a bullet to travel.
Note: Point to be noted is, as we know that at the starting point the bullet was in the rifle at rest position, so we will assume that the initial velocity of the bullet is zero. And we should note equations of motion to relate our given value to find out the acceleration of the bullet and time taken by the bullet.
Given:
Length of barrel, $S = 60cm$
As the velocity of bullet is given in $m/s$then, the distance should be in $m$
So, $S = 0.6m$
Final velocity, $V = 750m/s$
Initial velocity, $U = 0$
Formula used:
${V_{avg}} = \dfrac{{U + V}}{2}$
${V^2} = {U^2} + 2aS$
$\dfrac{{V - U}}{T} = a$
Complete Step by step solution:
To calculate the average velocity of the bullet, we use a formula in which the sum of initial and final velocity is divided by 2.
Now, we will calculate the average velocity
${V_{avg}} = \dfrac{{U + V}}{2}$
\[ = \dfrac{{0 + 750}}{2}\](Putting value of $U$and$V$)
$ = 375m/s$
Here we got an average velocity of the bullet which is $375m/s$
Now, you know there is a relationship between initial velocity, final velocity, distance, and acceleration
${V^2} = {U^2} + 2aS$(Here $a$is an acceleration)
${750^2} = 0 + 2a \times 0.6$(Putting values of $U,S$and$V$ )
$a = \dfrac{{562500}}{{1.2}} = 468750 = 46.88 \times {10^4}m/s$
Here we got acceleration, which we can use in the relation of final velocity, initial velocity, acceleration, and time, where we have everything except time, so we will calculate time from this relation.$\dfrac{{V - U}}{T} = a$
After simplification, we can write this equation, as below
$T = \dfrac{{V - U}}{a}$
$ = \dfrac{{750 - 0}}{{46.88 \times {{10}^4}}}$(Putting values of $U,a$and$V$)
$ = 15.998 \times {10^{ - 4}}s$
Here, we have calculated the time taken by a bullet to travel.
Note: Point to be noted is, as we know that at the starting point the bullet was in the rifle at rest position, so we will assume that the initial velocity of the bullet is zero. And we should note equations of motion to relate our given value to find out the acceleration of the bullet and time taken by the bullet.
Recently Updated Pages
Chemical Equation - Important Concepts and Tips for JEE

JEE Main 2022 (July 29th Shift 1) Chemistry Question Paper with Answer Key

Conduction, Transfer of Energy Important Concepts and Tips for JEE

JEE Analytical Method of Vector Addition Important Concepts and Tips

Atomic Size - Important Concepts and Tips for JEE

JEE Main 2022 (June 29th Shift 1) Maths Question Paper with Answer Key

Trending doubts
JEE Main 2026: Application Form Open, Exam Dates, Syllabus, Eligibility & Question Papers

JEE Main Correction Window 2026 Session 1 Dates Announced - Edit Form Details, Dates and Link

Equation of Trajectory in Projectile Motion: Derivation & Proof

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

Hybridisation in Chemistry – Concept, Types & Applications

Angle of Deviation in a Prism – Formula, Diagram & Applications

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Units And Measurements Class 11 Physics Chapter 1 CBSE Notes - 2025-26

NCERT Solutions For Class 11 Physics Chapter 8 Mechanical Properties Of Solids

Motion in a Straight Line Class 11 Physics Chapter 2 CBSE Notes - 2025-26

NCERT Solutions for Class 11 Physics Chapter 7 Gravitation 2025-26

Collision: Meaning, Types & Examples in Physics

