
A body is executing $SHM$, At a displacement $x$, its potential energy is ${E_1}$ and at a displacement $y$, its potential energy is ${E_2}$. Find its potential energy $E$ at displacement $(x + y)$
A. $\sqrt E = \sqrt {{E_1}} - \sqrt {{E_2}} $
B. $\sqrt E = \sqrt {{E_1}} + \sqrt {{E_2}} $
C. None of these
D. All of these
Answer
232.8k+ views
Hint:
A simple harmonic motion is one in which the restoring force constantly goes in the direction of the mean position and is directly proportional to the body's deviation from its mean position. To solve this question we need to understand the relationship between potential energy and displacement of the particle doing SHM.
Formula used:
${E} = \dfrac{1}{2}k{x^2}\,\,\,...(i)$
Complete step by step solution:
In order to know that according to the definition of potential energy, "It is the energy that depends on the relative placement of the various components of the system." Potential Energy develops in systems with pieces whose configuration or relative positions cause forces on each other that vary in magnitude.
In short, potential energy is the power that an object can store due to its position in relation to other things, internal tensions, electric charge, or other circumstances.
For a displacement $x$, the potential energy of a body performing simple harmonic motion is given by:
${E_1} = \dfrac{1}{2}k{x^2}\,\,\,...(i)$
Similarly, for a displacement$y$, the potential energy of a body performing simple harmonic motion is given by:
${E_2} = \dfrac{1}{2}k{y^2}\,\,\,...(ii)$
Now, for a displacement$(x + y)$, the potential energy of a body performing simple harmonic motion is given by:
$E = \dfrac{1}{2}k{(x + y)^2} \\$
$\Rightarrow E = \dfrac{1}{2}k({x^2} + {y^2} + 2xy) \\$
To determine the its potential energy $E$ at displacement $(x + y)$, from $(i)$and $(ii)$, then we obtain:
$E = {E_1} + {E_2} + k\sqrt {\dfrac{{2{E_1}}}{k}} \sqrt {\dfrac{{2{E_2}}}{k}} \\$
$\Rightarrow E = {E_1} + {E_2} + 2\sqrt {{E_1}{E_2}} \\$
$\Rightarrow \sqrt E = \sqrt {{E_1}} + \sqrt {{E_2}} \\$
Thus, the correct option is: (B) $\sqrt E = \sqrt {{E_1}} + \sqrt {{E_2}} $
Note:
It should be noted that to solve this problem, we must thoroughly analyse it and use the appropriate formulas. In addition to applying the proper formula to determine the potential energy at displacement $(x + y)$.
A simple harmonic motion is one in which the restoring force constantly goes in the direction of the mean position and is directly proportional to the body's deviation from its mean position. To solve this question we need to understand the relationship between potential energy and displacement of the particle doing SHM.
Formula used:
${E} = \dfrac{1}{2}k{x^2}\,\,\,...(i)$
Complete step by step solution:
In order to know that according to the definition of potential energy, "It is the energy that depends on the relative placement of the various components of the system." Potential Energy develops in systems with pieces whose configuration or relative positions cause forces on each other that vary in magnitude.
In short, potential energy is the power that an object can store due to its position in relation to other things, internal tensions, electric charge, or other circumstances.
For a displacement $x$, the potential energy of a body performing simple harmonic motion is given by:
${E_1} = \dfrac{1}{2}k{x^2}\,\,\,...(i)$
Similarly, for a displacement$y$, the potential energy of a body performing simple harmonic motion is given by:
${E_2} = \dfrac{1}{2}k{y^2}\,\,\,...(ii)$
Now, for a displacement$(x + y)$, the potential energy of a body performing simple harmonic motion is given by:
$E = \dfrac{1}{2}k{(x + y)^2} \\$
$\Rightarrow E = \dfrac{1}{2}k({x^2} + {y^2} + 2xy) \\$
To determine the its potential energy $E$ at displacement $(x + y)$, from $(i)$and $(ii)$, then we obtain:
$E = {E_1} + {E_2} + k\sqrt {\dfrac{{2{E_1}}}{k}} \sqrt {\dfrac{{2{E_2}}}{k}} \\$
$\Rightarrow E = {E_1} + {E_2} + 2\sqrt {{E_1}{E_2}} \\$
$\Rightarrow \sqrt E = \sqrt {{E_1}} + \sqrt {{E_2}} \\$
Thus, the correct option is: (B) $\sqrt E = \sqrt {{E_1}} + \sqrt {{E_2}} $
Note:
It should be noted that to solve this problem, we must thoroughly analyse it and use the appropriate formulas. In addition to applying the proper formula to determine the potential energy at displacement $(x + y)$.
Recently Updated Pages
JEE Main 2023 April 6 Shift 1 Question Paper with Answer Key

JEE Main 2023 April 6 Shift 2 Question Paper with Answer Key

JEE Main 2023 (January 31 Evening Shift) Question Paper with Solutions [PDF]

JEE Main 2023 January 30 Shift 2 Question Paper with Answer Key

JEE Main 2023 January 25 Shift 1 Question Paper with Answer Key

JEE Main 2023 January 24 Shift 2 Question Paper with Answer Key

Trending doubts
JEE Main 2026: Session 2 Registration Open, City Intimation Slip, Exam Dates, Syllabus & Eligibility

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

JEE Main Marking Scheme 2026- Paper-Wise Marks Distribution and Negative Marking Details

Understanding the Angle of Deviation in a Prism

Hybridisation in Chemistry – Concept, Types & Applications

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Laws of Motion Class 11 Physics Chapter 4 CBSE Notes - 2025-26

Waves Class 11 Physics Chapter 14 CBSE Notes - 2025-26

Mechanical Properties of Fluids Class 11 Physics Chapter 9 CBSE Notes - 2025-26

Thermodynamics Class 11 Physics Chapter 11 CBSE Notes - 2025-26

Units And Measurements Class 11 Physics Chapter 1 CBSE Notes - 2025-26

