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A balloon filled with helium ${32^ \circ }C$ and $1.7\,atm$ bursts. Immediately afterwards, the expansion of helium can be considered as:
A. Reversible Isothermal
B. Irreversible Isothermal
C. Reversible Adiabatic
D. Irreversible Adiabatic

Answer
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Hint: In the case of a problem based on thermodynamics, we know that all the parameters such as pressure, temperature, heat exchange, work done, etc., vary with the condition of systems and surroundings hence, analyze every option with the scientific approach and check which option seems to be more appropriate for the given situation.

Complete step by step solution:
According to the question, it is given that a balloon filled with helium at ${32^ \circ }C$ and $1.7\,atm$. It is clear that the pressure and temperature inside the balloon are greater than the Normal Temperature-Pressure NTP (${25^ \circ }C$ and $1\,atm$) condition. That’s why, if the balloon is filled with more helium after the present given condition, it will result in the bursting of the balloon.

Now, we know that as the bursting process is too quick, therefore, there is no time for the exchange of heat between the system and its surroundings. That means the process of expansion of helium is definitely ‘adiabatic’. Also, once the balloon bursts and helium flows outside from the balloon, there is no way to return back thus, the process is also ‘irreversible’.

Hence, the correct option is D.

Note: Since this is a problem of multiple-choice questions (theory-based) hence, it is essential that given conditions be analyzed very carefully to give a precise explanation. While writing an explanation of this kind of conceptual problem, always keep in mind to provide the exact reasons in support of your explanation.