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# A ball is thrown upward with a velocity of 100 m/s it will reach the ground after:(A) 10 s(B) 20 s(C) 5 s(D) 40 s

Last updated date: 12th Aug 2024
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Hint: We should know that velocity is defined as the rate change of displacement per unit time. Speed in a specific direction is also known as velocity. Velocity is equal to displacement divided by time. Speed, being a scalar quantity, is the rate at which an object covers distance. The average speed is the distance which is a scalar quantity per time ratio. On the other hand, velocity is a vector quantity; it is direction-aware. An object which moves in the negative direction has a negative velocity. If the object is slowing down then its acceleration vector is directed in the opposite direction as its motion in this case. Based on this we have to solve this question.

The time taken by gravity to reduce balls speed to zero. $0=100+(-10) \mathrm{t}$
The time that is considered as $\mathrm{t}=10 \mathrm{sec}$
Ball will be at its peak at $\mathrm{t}=10 \mathrm{sec}$. lt will take same amount of time to come back to ground total time $\mathrm{T}=20 \mathrm{sec}$.