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A, B and C are three points in a uniform electric field. The electric potential is

(A) Maximum at B
(B) Maximum at C
(C) Same at all three points A, B and C
(D) Maximum at A

Last updated date: 22nd Jun 2024
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Hint We know the perpendicular to the direction of electric field is equipotential, that is the potential does not change. We can use this at each point to compare the potential at the two given points in the question.

Complete step by step answer:
Since we know that any perpendicular drawn to the direction of electric field is equipotential in nature. Hence, the perpendicular drawn passing through point A will have the same potential as that of A. Similarly, we can do the same at point C and B and observe. We also know that if we move in the direction of potential then the electric field decreases as the potential gradient is equal to the negative of the electric field. So, we get that the potential at B is greater than the potential at C which in turn, is greater than the potential at A.

Hence, the correct option is A. Maximum at B

Additional information:
Equipotential Surfaces have the same electric potential everywhere. Surface of the conductor is an example. Work done is zero if a charge is moved between any points on this type of surface. Force and electric field are always at the right angle to the equipotential surface. It is impossible for two equipotential surfaces to intersect each other, because if this happens then it means that at the point of intersection there are two directions of electric field, which is impossible.

Equipotential surfaces have constant potential over its surface therefore the potential difference between any two points on this type of surface is zeroIn a group of equipotential surfaces, if the surfaces are close with each other, it means that the electric field is stronger at that point and if they are far apart then the field is weak.