$1N = Zkgf$ (approx.), then what is the value of $Z$?
(A) $0.1$
(B) $1$
(C) $10$
(D) $0$
Answer
244.8k+ views
Hint: To solve this question, we need to use the formula for the gravitational force on a body on the surface of the earth. Then we need to substitute the approximate value of the acceleration due to gravity on the surface of the earth. Also, we need to substitute the value of the force given in the question, after which we will get the required value of $Z$.
Formula used: The formula used to solve this question is given by
$F = mg$, here $F$ is the magnitude of the gravitational force acting on a body on a particle of mass $m$, and $g$ is the acceleration due to gravity on the surface of earth.
Complete step-by-step solution:
We know that the gravitational force acting on a body on the surface of the earth is given by the expression
$F = mg$
Now, we know that the value of the acceleration due to gravity on the surface of the earth is approximately equal to $10m/{s^2}$. The value of the force given in the question is equal to $1N$. Also, the mass of the body is given as $Zkg$. Therefore substituting $F = 1N$ $m = Zkg$ and $g = 10m/{s^2}$ in the above expression, we get
$1 = 10Z$
Dividing both sides by $10$, we get
$Z = \dfrac{1}{{10}}$
$ \Rightarrow Z = 0.1$
Thus, the value of $Z$ is equal to $0.1$.
Hence, the correct answer is option A.
Note: The unit of force given here is called one kilogram force. It is the non standard, gravitational metric unit of the force. It is a measure of the gravitational force exerted by the earth on an object having a mass equal to one kilogram.
Formula used: The formula used to solve this question is given by
$F = mg$, here $F$ is the magnitude of the gravitational force acting on a body on a particle of mass $m$, and $g$ is the acceleration due to gravity on the surface of earth.
Complete step-by-step solution:
We know that the gravitational force acting on a body on the surface of the earth is given by the expression
$F = mg$
Now, we know that the value of the acceleration due to gravity on the surface of the earth is approximately equal to $10m/{s^2}$. The value of the force given in the question is equal to $1N$. Also, the mass of the body is given as $Zkg$. Therefore substituting $F = 1N$ $m = Zkg$ and $g = 10m/{s^2}$ in the above expression, we get
$1 = 10Z$
Dividing both sides by $10$, we get
$Z = \dfrac{1}{{10}}$
$ \Rightarrow Z = 0.1$
Thus, the value of $Z$ is equal to $0.1$.
Hence, the correct answer is option A.
Note: The unit of force given here is called one kilogram force. It is the non standard, gravitational metric unit of the force. It is a measure of the gravitational force exerted by the earth on an object having a mass equal to one kilogram.
Recently Updated Pages
JEE Main 2026 Session 2 City Intimation Slip Releasing Soon

JEE Main 2027 Exam Date, Syllabus, Pattern, Registration, Eligibility & Updates

JEE Main 2026 Question Papers with Solutions PDF – Free Download

Is a Calculator Allowed in JEE Main 2026? Complete NTA Guidelines

JEE Main 2027 Syllabus: Based on Latest NTA Syllabus with PDF Download

JEE Main Exam Countdown Timer: Track Days Until Exam 2026

Trending doubts
JEE Main 2026: Exam Dates, Session 2 Updates, City Slip, Admit Card & Latest News

Ideal and Non-Ideal Solutions Explained for Class 12 Chemistry

Understanding the Angle of Deviation in a Prism

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Electric Field of a Uniformly Charged Ring

Derivation of Equation of Trajectory Explained for Students

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

JEE Advanced 2026 - Exam Date (Released), Syllabus, Registration, Eligibility, Preparation, and More

CBSE Notes Class 11 Physics Chapter 1 - Units And Measurements - 2025-26

Important Questions For Class 11 Physics Chapter 1 Units and Measurement - 2025-26

CBSE Notes Class 11 Physics Chapter 4 - Laws of Motion - 2025-26

CBSE Notes Class 11 Physics Chapter 14 - Waves - 2025-26

